In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real
Answer:
$20.60
Step-by-step explanation:
25.75x20%=5.15
25.75-5.15=20.60
2 5/9 +1 2/3
= 2 5/9 + 1 6/9
= 3 11/9
= 4 2/9
The graph of f(x) opens upward
For the values of x < -5 the function is a line with negative slope, for the values of x > - 5 the function is a line with positive slope.
The two lines intercept in the point (-5,-2). That is the vertex of the function; a minimum value. So, all the other points are above the line y = -2.
Step-by-step explanation:
Write an equation, of the slope intercept form. of the line passing through the points (2,3) and (4.6)
