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lidiya [134]
3 years ago
6

The front yard of a house is 80 feet long and 50 feet wide. The backyard of the house is 50 feet long and 40 feet wide. What is

the difference in area between the front yard and backyard?
Mathematics
2 answers:
Alisiya [41]3 years ago
7 0
Simple, the area is 80*50, 80*50=4,000 ft², the backyard has a dimension of 50*40=2,000 ft², subtract 4,000 from 2,000, 4,000-2,000=2,000 ft²
vaieri [72.5K]3 years ago
3 0
2,000 2 is the answer hope i helped

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24% of what number is 12?
vladimir1956 [14]
To get that, you have to multiply the both numbers, which is 24*12=288
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3 years ago
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Numbers divisible by 100 are divisible by 5.
Reptile [31]

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8 0
2 years ago
What does the x=?...
ra1l [238]

Answer:

75 ft

Step-by-step explanation:

Let 20/50 = 30/x

So,

20X = 30x50

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Which of these is not random?
Naily [24]

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6 0
3 years ago
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
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time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
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We solve this system of equations:

10t=15(t-3)
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Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
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