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lidiya [134]
3 years ago
6

The front yard of a house is 80 feet long and 50 feet wide. The backyard of the house is 50 feet long and 40 feet wide. What is

the difference in area between the front yard and backyard?
Mathematics
2 answers:
Alisiya [41]3 years ago
7 0
Simple, the area is 80*50, 80*50=4,000 ft², the backyard has a dimension of 50*40=2,000 ft², subtract 4,000 from 2,000, 4,000-2,000=2,000 ft²
vaieri [72.5K]3 years ago
3 0
2,000 2 is the answer hope i helped

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Bezzdna [24]

Given :

You order 1.5 pounds of turkey at the deli.

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What absolute value inequality can be used to describe the tolerance of the weight of the turkey.

Solution :

It is given that the weight cannot be less that 1.46 pounds.

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Combining equation 1 and 2 we get :

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Answer:

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Step-by-step explanation:

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vagabundo [1.1K]

Answer:

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