Hey! I hope I understood the question correctly, I haven’t done compound inequalities in so long! Here’s my try:
X<-4
The tan is negative in the 2nd and 4th quadrants, knowing this, the angle that equals the value that tan = 1 in the first quadrant is the tan 45° = 1, but the question restrict for 3pi/2 < theta < 2pi, so it's the same as 270° < theta < 360° (4° Quadrant), then moving the tan 45° = to this quadrant the value will be negative, tan in 4°Q = tan(360 - 45=315°) = -1.
sec theta = 1/cos theta
cos 45° =
cos values in 4°Q will be positives, so it doesn't change the signal.
sec 315° = 1/cos 315°
sec 315° = 1/square root (2)/2
sec 315 = 1/1 x 2/sqroot(2)
Answer:
The answer is 12
Step-by-step explanation:
For coin there are two possible outcomes: head or tail.
For 3-color spinner you have three possible outcomes: red, blue and yellow.
Tossing a coin once and then spinning a 3-color spinner once you'll have 6 posiible outcomes:
- head + red;
- head + blue;
- head + yellow;
- tail + red;
- tail + blue;
- tail + yellow.