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Alex73 [517]
3 years ago
7

Martin is interested in joining a gym and has researched the cost of two gyms close to his

Mathematics
1 answer:
pochemuha3 years ago
8 0

Answer:

I suppose that you want to find which gym will be cheaper for you.

We have two equations:

• Gym A: 30m + 50

• Gym B: 10m + 100

First, let's find the value of m such that both gyms cost exactly the same:

30*m + 50 = 10*m + 100

Let's solve this for m

30*m - 10*m = 100 - 50

20*m = 50

m = 50/20 = 2.5

now:

for m < 2.5, Gym A will be cheaper, because the y-intercept is smaller.

for m > 2.5, Gym B will be cheaper, because the slope is smaller,

Then depending on the number of months that Martin wants to go to the gym, he can se the info above to pick the one that is cheaper.

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Step-by-step explanation:

3^3-5x9+6-29

calculate exponents 3^3=27

now write as; 27-5x9+6-29

now multiply and divide (left to right) 5x9=45

now rewrite as 27-45+6-29

now add and subtract(left to right) 27-45+6-29= -41

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-3/2 is less than 3x solve​
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anything above 1

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5 0
2 years ago
How to solve this (b) ???​
vladimir1956 [14]

(b). → Simplify: [{5^(x-+1) + 5^x}/{6×5^x}]

= [{5^(x+1+x)}/{6×5^x}]

= [{5^(2x+1)}/{6×5^x}]

= [{5^(2x+1)}/{6×5^x}]

= [{5^(2x+1-x)}/6]

= [{5^(x+1)}/6]Ans.

(c). 4a³b²

= 4(3)³(-2)²

Since, a = 3 and b = -2.

so,

= 4(3*3*3)(-2*-2)

= 4(27)(4)

= 108(4)

= 432Ans.

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