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lora16 [44]
2 years ago
15

How to solve this (b) ???​

Mathematics
1 answer:
vladimir1956 [14]2 years ago
5 0

(b). → Simplify: [{5^(x-+1) + 5^x}/{6×5^x}]

= [{5^(x+1+x)}/{6×5^x}]

= [{5^(2x+1)}/{6×5^x}]

= [{5^(2x+1)}/{6×5^x}]

= [{5^(2x+1-x)}/6]

= [{5^(x+1)}/6]Ans.

(c). 4a³b²

= 4(3)³(-2)²

Since, a = 3 and b = -2.

so,

= 4(3*3*3)(-2*-2)

= 4(27)(4)

= 108(4)

= 432Ans.

<u>also</u><u> </u><u>read</u><u> similar</u><u> questions</u><u>:</u> simplify 6/x-6+3x/x+5-1/(x-6)(x+5)..

brainly.com/question/9027174?referrer

simplify the equation simplify x^5/8/x^1/6..

brainly.com/question/84093?referrer

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Answer:

a) 74.0353 < u <  74.0367

b) 74.036 < u

Step-by-step explanation:

Given:

- Sample size n = 15

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- Sample mean x_bar = 74.036

Find:

A) Calculate the 99% two-sided confidence interval on the true mean piston diameter.

Solution:

- For 99% CI, We have a = 0.01 , and Z_a/2 = 2.58

------> (x_bar - Z_a/2*s.d / sqrt(n)) < u <  (x_bar + Z_a/2*s.d / sqrt(n))

------> (74.036 - 2.58*0.0001 / sqrt(15)) < u <  (74.036 + 2.58*0.0001 / sqrt(15))

------>                               74.0353 < u <  74.0367

Find:

B) Calculate the 95% one-sided lower confidence interval on the true mean piston diameter.

Solution:

- For 95% lower CI, We have a = 0.05 , and Z_a = 1.645

------> (x_bar - Z_a/2*s.d / sqrt(n)) < u

------> (74.036 - 1.645*0.0001 / sqrt(15)) < u

------>                               74.036 < u

5 0
3 years ago
PLS HELP ASAP ILL GIVE BRAINLKEST THANKS
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Answer:

C

Step-by-step explanation:

y = 10

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The y intercept is 0 and the line runs through (0,0)

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Equation

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3 years ago
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Answer:

➩ 2,250 envelopes.

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Given that, Nicole buys 125 envelopes per box for her home office.

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Answer:

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Step-by-step explanation:

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3 years ago
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