WILL GIVE BRANLIEST TO WHOEVER ANSWERS CORRECTLY. Find quadratic equation for the x-intercepts of (6,0) and (26,0)
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we have
<u>Statements</u>
<u>case A)</u> The graph is a straight line.
The statement is True
Because, this is a linear equation (see the attached figure)
<u>case B)</u> The line passes through the origin.
The statement is False
Because the point is not a solution of the equation
Verify
Substitute the value of x and y in the equation
------> is not true
the point is not a solution
therefore
The line does not pass through the origin
<u>case C)</u> The line passes through the point
The statement is True
Because the point is a solution of the equation
Verify
Substitute the value of x and y in the equation
------> is true
the point is a solution
therefore
The line passes through the point
<u>case D) </u>The slope of the line is
The statement is False
Because, the slope of the line is
<u>case E)</u> The y-intercept of the line is
The statement is False
we know that
The y-intercept is the value of y when the value of x is equal to zero
so
For
find the value of y
the y-intercept is equal to
We know that
X²+y²=9 -------> X²+y²=3²
is the equation of a circle with center (0,0) and radius r=3 units
so
<span>the translation of four units to the right and three units down is equals to move the center (0,0)--------> (0+4,0-3)------> (4.-3)
the new center of the circle is (4,-3)
the new equation is
(x-4)</span>²+(y+3)²=3²
see the attached figure
X²+y²=9 -------> X²+y²=3²
is the equation of a circle with center (0,0) and radius r=3 units
so
<span>the translation of four units to the right and three units down is equals to move the center (0,0)--------> (0+4,0-3)------> (4.-3)
the new center of the circle is (4,-3)
the new equation is
(x-4)</span>²+(y+3)²=3²
see the attached figure