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liubo4ka [24]
3 years ago
13

If log10 y = 2. what does y equal?

Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0

Answer:

log_{10}  (100) = 2

Step-by-step explanation:

Here, the given expression is:

log_{10}  (y) = 2

Now, by logarithm rules, we know

if  log_{b}(x) = z

, then x =b^{z}

Comparing here, b = 10  and  z = 2

⇒ y  =   10^{2}  = 100

or, log_{10}  (100) = 2

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Leni [432]
102/87 = 3*34/(3*29) = 34/29
4 0
3 years ago
Help need to be done soon​
nikitadnepr [17]

<u>Given</u>:

Given that the measure of arc DF is 162°

We need to determine the measure of ∠E

<u>Measure of ∠E:</u>

The measure of ∠E can be determined using the inscribed angle theorem.

Thus, by inscribed angle theorem, we have;

\angle E=\frac{1}{2}(m \widehat{DF})

Substituting m \widehat{DF}=162^{\circ}, we get;

\angle E=\frac{1}{2}(162^{\circ})

Dividing, we get;

\angle E=81^{\circ}

Thus, the measure of ∠E is 81°

6 0
3 years ago
The product of five and a number, increased by 9 is equal to fifteen less than three times then
bonufazy [111]

Answer:

x = -12

Step-by-step explanation:

Let x be the number.

The product of 5 and x increased by 9 is equal to 15 less than 3 times x.

5x + 9 = 3x - 15.

We can isolate x, getting (5-3)x = -15-9

Then we can solve:

2x = -24

x = -12.

8 0
3 years ago
Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and
uysha [10]

Answer:

\frac{x^{2}}{36} - \frac{y^{2}}{64}=1

Step-by-step explanation:

Given an hyperbola with the following conditions:

  • Foci at (-10,0) and (10,0)
  • x-intercept +/- 6;

The following holds:

  • The center is midway between the foci, so the center must be at (h, k) = (0, 0).
  • The foci are 10 units to either side of the center, so c = 10 and c^2 = 100
  • The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and a^2 = 36.

Then, a^2+b^2=c^2\\b^2=100-36=64

Therefore, substituting a^2 = 36. and b^2=64 into the standard form

\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1

4 0
3 years ago
Describe the overall shape of this distribution. Explain your answer in complete sentences.
Stolb23 [73]

I DONT  KNOW  KJHBUGGYTFYU GVFTY YGFTRF 8IJFTS GUGFRX

4 0
3 years ago
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