Ask question

Ask question

All categories

Natali5045456 [20]

3 years ago

12

A garden has four sides that are all the same length. Each side measures x + 5 units. The garden’s perimeter is 144 units. What

is the value of x?
Show your work for full points or brainlyest answer

1 answer:

Elenna [48]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

Hanson and his classmates placed colored blocks on a scale during a science lab. The blue block weighed 8.1 pounds and the green

Alexeev081 [22]

Answer:

4.342

Step-by-step explanation:

8.1 - 3.758 = 4.342

When you are trying to find the amount of difference between two values you subtract the value less than the other and there you go, the solution!

I hope it was as simple as that and that this helped!

3 0

2 years ago

Question 1. If the perimeter of Rectangle ABCD is 34y+2. What is the width?

Savatey [412]

Answer:

Question 1. If the perimeter of Rectangle ABCD is 34y+2. What is the width?

Question 2. What is the area of Rectangle ABCD in terms of y?

Question 3. If the perimeter of the rectangle is 70. What is it’s area?

Question 4. What are the length and width of the rectangle?

6 0

3 years ago

MATLAB Simulation. Develop a Matlab script to simulate the modulation of a 30 kHz carrier with a 0.5 kHz message signal. Use 40%

iren2701 [21]

Answer:

MATLAB code for DSB-SC modulation.

fc=154000; % carrier signal frequency

fm=fc/10; % message signal frequency

fs=100*fc;

t=0:1/fs:4/fm;

xc=cos(2*pi*fc*t);

xm=10*cos(2*pi*fm*t); % amplitude of sinusodial is 10

figure(1)

subplot(2,1,1),plot(t,xc);

title('carrier signal of 154 khz');

xlabel('time (sec)');

ylabel('amplitude');

subplot(2,1,2),plot(t,xm);

title('message signal of 15.4 khz');

xlabel('time (sec)');

ylabel('amplitude');

% DSB-SC MODULATION

z1= xm.*xc;

figure(2)

subplot(2,1,1),plot(t,z1);

title('DSB-SC MODULATION IN TIME DAOMAIN');

xlabel('time (sec)');

ylabel('amplitude');

l1=length(z1);

f=linspace(-fs/2,fs/2,l1);

Z1=fftshift(fft(z1,l1)/l1);

subplot(2,1,2),plot(f,abs(Z1));

title('DSB SC MODULATION IN FREQUENCY DOMAIN');

xlabel('frequency(hz)');

ylabel('amplitude');

axis([-200000 200000 0 3]);

Step-by-step explanation:

6 0

3 years ago

Simplify (-2/5) divided by (8/9) times (2/9) divided by (-1/3) explain and show all steps

spayn [35]

Simplification of (-2/5) divided by (8/9) times (2/9) divided by (-1/3) is 0.3

<em><u>Solution:</u></em>

Given that,

Simplify (-2/5) divided by (8/9) times (2/9) divided by (-1/3)

Here "times" represent multiplication

<em><u>The above sentence can be written mathematically as:</u></em>

$\frac{-2}{5} \div \frac{8}{9} \times \frac{2}{9} \div \frac{-1}{3}$

Convert the problem to multiplication by changing the division sign to multiplication. When we change division sign to multiplication, the fraction becomes reciprocal

$\rightarrow \frac{-2}{5} \times \frac{9}{8} \times \frac{2}{9} \times \frac{3}{-1}$

Cancelling the common terms in numerator and denominator,

$\rightarrow \frac{-2}{5} \times \frac{1}{8} \times \frac{2}{1} \times \frac{3}{-1}$

Multiplying terms in numerator and denominator,

$\rightarrow \frac{-12}{-40}$

Negative sign in numerator and denominator cancels each other

$\rightarrow \frac{-12}{-40} = \frac{12}{40}$

Reducing to lowest terms we get,

$\rightarrow \frac{12}{40} = \frac{3}{10}$

In decimal form we get,

$\rightarrow \frac{3}{10} = 0.3$

Thus solution to given expression is 0.3

8 0

3 years ago

The radius of a circle is 5 cm. What is the radius of another circle whose area is 25 times that of the first one?

zhannawk [14.2K]

Answer:

Step-by-step explanation:

a₁ = πr₁⁵ = 25π cm²

a₂ = 25(25π) = 625π cm²

r₂ = 25 cm

4 0

3 years ago