So
y=ax^2+bx+c
(x,y)
sub the points and solve
(4.28,6.48)
6.48=a(4.28)^2+b(4.28)+c
(12.61,15.04)
15.04=a(12.61)^2+b(12.61)+c
well, for 3 variables, we need equations and therefor 3 points
maybe we are supposed to assume it starts at (0,0)
so then
0=a(0)^2+b(0)+c
0=c
so then
6.48=a(4.28)^2+b(4.28)
15.04=a(12.61)^2+b(12.61)
solve for a by subsitution
first equation, minut a(4.28)^2 from both sides
6.48-a(4.28)^2=b(4.28)
divide both sides by 4.28
(6.48/4.28)-4.28a=b
sub that for b in other equation
15.04=a(12.61)^2+b(12.61)
15.04=a(12.61)^2+((6.48/4.28)-4.28a)(12.61)
expand
15.04 =a(12.61)^2+(81.7128/4.28)-53.9708a
minus (81.7128/4.28) both sides
15.04-(81.7128/4.28)=a(12.61)^2-53.9708a
15.04-(81.7128/4.28)=a((12.61)^2-53.9708)
(15.04-(81.7128/4.28))/(((12.61)^2-53.9708))=a
that's the exact value of a
to find b, subsitute to get
(6.48/4.28)-4.28((15.04-(81.7128/4.28))/(((12.61)^2-53.9708)))=b
if we aprox
a≈-0.038573167896199
b≈1.6791118501845
so then the equation is
y=-0.038573167896199x²+1.6791118501845x
Answer:
1/2
Step-by-step explanation:
1) the sample space is 1 through 6
2) numbers less than 4 on the number cube 1, 2, and 3 3#s
total amount of #s is 6
probability = numbers less than 4/total amount of #s:
3/6
1/2
180-53 is 127 angle 6 and 3 would be the same so your answer is 127
Answer:
a) No.
b) Yes.
c) Yes.
Step-by-step explanation:
a) No.
As being without replacement, the probabilities of each color in each draw change depending on the previous draws.
This is best modeled by an hypergeometric distribution.
b) Yes.
As being with replacement, the probabilities for each color is constant.
Also, there are only two colors, so the "success", with probability p, can be associated with the color red, and the "failure", with probability (1-p), with the color blue, for example.
(With more than two colors, it should be "red" and "not red", allowing only two possibilities).
c) Yes.
The answer is binary (Yes or No) and the probabilities are constant, so it can be represented as a binomial experiment.
Let the shortest side be = a, then side b = 2·a and side c = (b + 24)
We are given that a + b + c = 84
Substituting for b and c
a + 2·a + (a + 24) = 84
4·a + 24 = 84
4·a = 84 - 24 = 60
a = 60/4 = 15 feet
b = 2·15 = 30 feet
c = 15 + 24 = 39 feet
sorry if i am wrong