X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
I know, you have to divide 90 by what ever the length is, then you have to figure out where the points are. So it should be.... D!!!
The period will be the length for one cycle of the function.
answer: 10
Keep your mom, you only have one. But anyway;
Use the Pythagorean Theorem: A^2 + B^2 = C^2
12^2 + 21^2 = C^2
144 + 441 = C^2
585 = C^2
square root of 585 = approximately 24.2
Children=x
Adults=y
* x + y =275 => x = 275 - y
* 3.00x + 6.40y = 1284 <=> 3.00(275 - y) + 6.40y = 1284 <=> ... <=> y = 135 => x = 275 - 135 = 140
Children: 140
Adults: 135
