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mel-nik [20]
3 years ago
11

In a class full of men and women,

Mathematics
1 answer:
lana66690 [7]3 years ago
8 0
The ratio of men to women would be 3/5 or 3:5
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How to solve stacked similar figures
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Answer:

Step-by-step explanation:

You can identify similar polygons by comparing their corresponding angles and sides. As you see in the following figure, quadrilateral WXYZ is the same shape as quadrilateral ABCD, but it’s ten times larger (though not drawn to scale, of course). These quadrilaterals are therefore similar.

similar polygons: For two polygons to be similar, both of the following must be true:

Corresponding angles are congruent.

Corresponding sides are proportional.

To fully understand this definition, you have to know what corresponding angles and corresponding sides mean. (Maybe you’ve already figured this out by just looking at the figure.) Here’s the lowdown on corresponding. In the figure, if you expand ABCD to the same size as WXYZ and slide it to the right, it’d stack perfectly on top of WXYZ.

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brians kite is flying above a field at the end of 65 m string. if the angle of elevation to the kite is 70°. how high is the kit
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<span>61.08 m
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7 0
3 years ago
9. If each of the following pairs represents a pair of equivalent rational
Oksi-84 [34.3K]

Answer:

-35/6

Step-by-step explanation:

We need to find the value of x , And the given pair of Rational numbers are equal.

<u>Question</u><u> </u><u>(</u><u>I)</u><u> </u><u>:</u><u>-</u><u> </u>

→ 3/4 = 7/x

→ 7/x = 3/4

→ 1/x = 3/4 × 1/7

→ 1/x = 3/28

→ x = 28/3

<u>Question</u><u> (</u><u>ii)</u><u> </u><u>:</u><u>-</u><u> </u>

→ x/7 = -5/6

→ x = -5/6 × 7

→ x = -35/6

<h3>• Hence the value of x is -35/6 .</h3>
7 0
3 years ago
Exercise 6.13 presents the results of a poll evaluating support for the health care public option in 2009, reporting that 52% of
sleet_krkn [62]

Answer:

A sample size of 6755 or higher would be appropriate.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error M is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

52% of Independents in the sample opposed the public option.

This means that p = 0.52

If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

Sample size of size n or higher when M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.52*0.48}{n}}

0.01\sqrt{n} = 0.8218

\sqrt{n} = \frac{0.8218}{0.01}

\sqrt{n} = 82.18

\sqrt{n}^{2} = (82.18)^{2}

n = 6754.2

A sample size of 6755 or higher would be appropriate.

3 0
3 years ago
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