n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
-----------------------------------------------------
ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
----------------------------------------------------------
n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
Yes, it is a right triangle.
Step-by-step explanation:
Take all the zero's away and multiply the numbers that are left.
which is 1*1=1 now add all of the zeros to that one which will turn it into
10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
which is the answer
I don't exactly get what your supposed to do but I thought it like this:
T V
3000 0
3000 4000
5000 4000
5000 8000
the last two are the final answers on how long the ran or it could be Terrel ran 5 kilometers while Victor ran 8 kilometers, but still idk what exactly your supposed to put
D = 14
1/6d + 2/3 = 1/4d - 1/2
2d + 4*2 = 3d - 6
2d - 3d = -6-8
-d = -14
d = 14
