Answer:
The probability that a randomly selected call time will be less than 30 seconds is 0.7443.
Step-by-step explanation:
We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.
Let X = caller times at a customer service center
The probability distribution (pdf) of the exponential distribution is given by;

Here,
= exponential parameter
Now, the mean of the exponential distribution is given by;
Mean =
So,
⇒
SO, X ~ Exp(
)
To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;
; x > 0
Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)
P(X < 30) =
= 1 - 0.2557
= 0.7443
THE answer would be 38. letter C.
Change 48% to 0.48
0.48 x 18 = 8.64
rounded would be 9
Answer:
D-70
Step-by-step explanation:
It is a combination C(8,4)
2) 5= 7 + -2
3) (-8) + 8 = 0
8) 3 + 5 = 8
9) 7 + 5 = 12
10) 4 = -8 + 4