Answer:
4y²−38y−20
Step-by-step explanation:
(y−10)(4y+2)
=(y+−10)(4y+2)
=(y)(4y)+(y)(2)+(−10)(4y)+(−10)(2)
=4y²+2y−40y−20
=4y²−38y−20
please mark me brainliest!
Answer:
3, in both a), b)
Step-by-step explanation:
a) The slope of the line tangent to the curve that passes through the point (2,-10) is equal to the derivative of p at x=2.
Using differentiation rules (power rule and sum rule), the derivative of p(x) for any x is 
. In particular, the value we are looking for is 
.
If you would like to compute the equation of the tangent line, we can use the point-slope equation to get 
b) The instantaneus rate of change is also equal to the derivative of P at the point x=2, that is, P'(2). This is equal to 
.
Answer:
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.
Step-by-step explanation:
Given that;
mean x" = 5.4
standard deviation σ = 0.7
n = 6
Null hypothesis H₀ : μ = 5.0
Alternative hypothesis H₁ : μ > 5.0
∝ = 0.025
now,
t = ( 5.4 - 5.0) / ( 0.7/√6) = 0.4 / 0.2857 = 1.4
degree of freedom df = n-1 = 6 - 1 = 5
T critical = 2.571
Therefore; t < T critical,
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.
X=5.4 because that is how i figured out the answer and I didn’t even figure out
