A rope that is 168 ft long is to be cut into three pieces such that the second piece is 6 ft less than three times the first, an
d the third is 2 ft more than two-thirds of the second. Find the length of the longest piece.
1 answer:
Answer:
Length of longest piece is 82 ft
Step-by-step explanation:
Let the measure of the second piece be x
First piece be y
second piece is 6 ft less than 3 times the first
x = 3y - 6
y = (x + 6)/3
3rd piece = 2 + 2/3 * x
= 2 + 2x/3
Adding all equals 168
we only add in terms of x
so we have;
x + (x + 6)/3 + 2 + 2x/3 = 168
Multiply through by 3
3x + x + 6 + 6 + 2x = 504
6x + 12 = 504
6x = 492
x = 492/6
x = 82 ft
So the other pieces are
(x + 6)/3 = 82+6/3 = 88/3 ft
And lastly
2 + 2x/3
= 2 + 164/3 ft
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:)
Answer:
From top to bottom:
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Step-by-step explanation:
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