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hodyreva [135]
3 years ago
10

(5n2 – 4nm - 9m²) + (7n2 + 4nm +8m²) =

Mathematics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

\left(5n^2-4nm-9m^2\right)+\left(7n^2+4nm+8m^2\right)=12n^2-m^2

Step-by-step explanation:

Given the expression

\left(5n^2\:-\:4nm\:-\:9m^2\right)\:+\:\left(7n^2\:+\:4nm\:+8m^2\right)

Remove parentheses: (a) = a

=5n^2-4nm-9m^2+7n^2+4nm+8m^2

Group like terms

=5n^2+7n^2-4nm+4nm-9m^2+8m^2

Add similar elements: 5n^2+7n^2=12n^2

=12n^2-4nm+4nm-9m^2+8m^2

Add similar elements: -4nm+4nm=0

=12n^2-9m^2+8m^2

Add similar elements:  -9m^2+8m^2=-m^2

=12n^2-m^2

Therefore, we conclude that:

\left(5n^2-4nm-9m^2\right)+\left(7n^2+4nm+8m^2\right)=12n^2-m^2

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y < x – 2 and y > x + 1

Step-by-step explanation:

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son4ous [18]

Answer:

18.0

Step-by-step explanation:

==>Given:

Triangle with sides, 16, 30, and x, and a measure of an angle corresponding to x = 30°

==>Required:

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==>Solution:

Using the Cosine rule: c² = a² + b² - 2abcos(C)

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3 years ago
Help! <br> Which expression is equivalent? <br> On edge
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Answer: Choice B

x^{1/8}y^{8}

======================================================

Explanation:

The two rules we use are

(a*b)^c = a^c*b^c

(a^b)^c = a^{b*c}

When applying the first rule to the expression your teacher gave you, we can say that:

\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}

Then applying the second rule lets us say

\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}

Therefore,

\left(x^{1/4}y^{16}\right)^{1/2}  = x^{1/8}y^{8}

-------------

In short, we just multiplied each exponent inside by the outer exponent 1/2.

So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.

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Sergeu [11.5K]
The correct answer is 4> -3
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2 years ago
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