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lana [24]
3 years ago
15

Help me with the part b!

Mathematics
1 answer:
ra1l [238]3 years ago
7 0
Average speed =   (distance final - distance initial)/(time final - time initial)
Average speed = (30-0)km /(100 -0)min = 3/10 km/min

3/10 km/min *60 min/1 h = 180/10 km/h= 18 km/h
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Phillip bought 12 used cds and dvds. CDs cost 2 each and dvds cost 3 each. He spent 32 not including tax. How many dvds did Phil
Feliz [49]

Answer:

Eight

Step-by-step explanation:

We have two conditions:

(1)           C + D  = 12

(2)      2C + 3D = 32          Subtract D from each side of Equation (1)

                    C = 12 - D     Multiply both sides by 5

2(12 – D) + 3D = 32          Remove parentheses

24 – 2D + 3D = 32          Combine like terms

           24 + D = 32           Subtract D from each side

                   D = 8

Philip bought eight DVDs.

7 0
3 years ago
B.
klemol [59]
B because it’s the right answer and um not lying no cap
8 0
3 years ago
Write an equation for a line perpendicular to y=3x−1 and passing through the point (-9,4)
Vedmedyk [2.9K]

Answer:

y=-1/3x+1

Step-by-step explanation:

(picture explains)

6 0
3 years ago
Please Help Brainliest to whoever can give a clear explanation for this problem!
iren [92.7K]

See the attached sketch. Let \beta denote angle ABC and \beta' denote angle CBD. Then \beta'=2\beta.

From the sketch, we see that

\tan\beta=\dfrac15

\tan(\beta+\beta')=\tan(3\beta)=\dfrac{AD}5

Write \tan(3\beta) in terms of \tan\beta. Recall the angle sum identity for tangent:

\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

This gives us

\tan(3\beta)=\dfrac{\tan\beta+\frac{2\tan\beta}{1-\tan^2\beta}}{1-\tan\beta\cdot\frac{2\tan\beta}{1-\tan^2\beta}}=\dfrac{\tan\beta(\tan^2\beta-3)}{3\tan^2\beta-1}

and plugging in \tan\beta=\frac15 leaves us with

\tan(3\beta)=\dfrac{37}{55}

and so AD = 5 * 37/55 = 37/11.

6 0
3 years ago
Identify the factors of
Alchen [17]

Answer:

I think option one

(X + 8)(x - 3)......

5 0
3 years ago
Read 2 more answers
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