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sladkih [1.3K]
3 years ago
13

Find the final value if £3500 is invested for 6 years at 6.9% p.a. Final value = £

Mathematics
2 answers:
gulaghasi [49]3 years ago
5 0

                  = Answer:

Step-by-step explanation:

interest= 3500 * 6 * 6.9* 1/100

                  = 4949

Final value = £ 3500 + 1449

                  = 4949

faust18 [17]3 years ago
4 0

Principal=P=3500

Time=T=6years

Rate of interest =R=6.9

Interest be I

\\ \sf\longmapsto  I=\dfrac{PRT}{100}

\\ \sf\longmapsto  I=\dfrac{3500(6)(6.9)}{100}

\\ \sf\longmapsto  I=\dfrac{144900}{100}

\\ \sf\longmapsto  I=1449

Now

Final value=3500+1449=4949

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A square garden plot measures 180 square feet. A second square garden plot measures 320 square feet. How many more feet of fence
REY [17]

The second garden plot will require 8√5 feet more fence than the first garden plot.

Further explanation:

In order to find the fence, we have to find the perimeter of both squares

So,

Area of Square 1: A1=180 square feet

Area of Square 2: A2=320 Square feet

Let x be the side of square 1:

Then,

A_1=x^2\\180=x^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{180}=\sqrt{x^2}\\x=\sqrt{2*2*3*3*5}\\x=\sqrt{2^2*3^2*5}\\x=2*3\sqrt{5}\\x=6\sqrt{5}

For second square:

Let y be the side of second square

A_2=y^2\\320=y^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{320}=\sqrt{y^2}\\y=\sqrt{2*2*2*2*2*2*5}\\y=\sqrt{2^2*2^2*2^2*5}\\y=2*2*2\sqrt{5}\\y=8\sqrt{5}

Perimeter of First Square:

P_1=4x\\=4(6\sqrt{5})\\=24\sqrt{5}\ feet

Perimeter of Second Square:

P_2=4y\\=4(8\sqrt{5})\\=32\sqrt{5}\ feet

The smaller perimeter will be subtracted from larger perimeter to find that how much more fence will be needed.

P_2-P_1=32\sqrt{5}-24\sqrt{5}\\=(32-24)\sqrt{5}\\=8\sqrt{5}\ feet

The second garden plot will require 8√5 feet more fence than the first garden plot.

Keywords: Radicals, Operations on Radicals

Learn more about radicals at:

  • brainly.com/question/13219835
  • brainly.com/question/1836777

#LearnwithBrainly

6 0
4 years ago
parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm. point F is on RS exactly 5 cm from S. let T be the intersection of PF
Doss [256]

<u>Solution-</u>

Given that,

In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.

Then considering ΔPQT and ΔSTF,

1-    ∠FTS ≅ ∠PTQ            ( ∵ These two are vertical angles)

2-   ∠TFS ≅ ∠TPQ            ( ∵ These two are alternate interior angles)

3-   ∠TSF ≅ ∠TQP            ( ∵ These two are also alternate interior angles)

<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>

∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS} =\frac{TP}{TF}

As QS = TQ + TS = 10 (given)

If TS is x, then TQ will be 10-x. Then putting these values in the equation

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS}

\Rightarrow \frac{8}{5} =\frac{10-x}{x}

\Rightarrow x=3.85

∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm




5 0
4 years ago
List multiples of 6 between 20 and 50.​
xenn [34]

Answer:

6,12,18,24,30,36,42,48,54,69

5 0
3 years ago
Read 2 more answers
The measure of arc LK is?
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Because MK is a diameter, then angle L is a right angle. We already know that the measure of angle K is 50, so the measure of angle M has to be 40 because of the triangle angle-sum theorem. The rule for inscribed angles and the arcs they cut off is that the angle is half the measure of its intercepted arc or, likewise, the arc is twice the measure of the angle that cuts it off. Since arc LK is across from angle M and is cut off by angle M, then arc LK is twice the measure of angle M, and is 80. That's the same reason why angle L is 90; arc MK is a semi-circle, with a degree measure of 180, and angle L is half of that.

Arc LK = 80

5 0
3 years ago
Someone help me plz???
svetoff [14.1K]

Answer:

12ft

Step-by-step explanation:

Hope I helped!

May you give me brainliest if it is right?

8 0
3 years ago
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