Well if you have the coordinates (2,2) and (4,4) you plug in the y from the second cords for y2
So it would be 4-2/4-2 and 2/2 equals 1
1 would be the m in y=MX+b
Then plug one set of coords in y=MX+b
2=1x+b
I know it's confusing to understand but I tried lol
Well .03 is equal to 3/100 so it is already in simplest form
Answer:
unbounded region
A feasible region that cannot be enclosed in a closed figure is known as an unbounded region. A feasible region is a set of all possible points of an optimization problem that satisfy the problem's constraints; feasible sets may be bounded or unbounded.
Step-by-step explanation:
The answer is <span>f(x) = 2x2 + 3x – 3
</span>
f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term
<u>We are looking for a = 2, c = -3</u>
Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.
In the function: <span>f(x) = –3x2 – 3x + 2
</span>a = -3
c = 2
In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3
