Our inter-arrival time follows Poisson distribution with parameter 14 which is in hour so first we have to calculate this in minutes as we have to calculate probability in minutes.

So converting 14 into minutes will give $\frac{14}{60}$ =0.233

Let X=inter-arrival time between two customers

and here $\lambda$ = 0.233

Probability(X is less than or equal to 2 minutes) = P(X=0) + P(X=1) + P(X=2)

Now the Poisson distribution has PDF = $\frac{\exp ^{-\lambda }\times \lambda ^{X}}{X!}$

So P(X = 0) = $\frac{\exp ^{-0.233}\times 0.233^{0}}{0!}$ = 0.79215

P(X= 1) = $\frac{\exp ^{-0.233}\times 0.233^{1}}{1!}$ = 0.18457

P(X=2) = $\frac{\exp ^{-0.233}\times 0.233^{2}}{2!}$ = 0.02150

Now adding all three probability gives = 0.79215 +0.18457 + 0.02150=0.99822

3 0

3 years ago

a rectangular prism measures 2 in by 4 in by 8 in what is the side length of a cube with the same volume

Umnica [9.8K]

<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ First find the volume of the rectangular prism:

2 x 4 x 8 = 64

Now you need to cube root it, this would be because all lengths of a cube are equal:

$\sqrt[3]{64} = 4$

The side length would be 4 inches.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0

3 years ago