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3 years ago

Can you help me on 19 and 20?!

Mathematics

1 answer:

rosijanka [135]3 years ago

6 0

19 : yeah we connect the points but not always so False

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PLEASE HELP

Ronch [10]

Answer:

1 and 5

Step-by-step explanation:

The squares have a side length of 10 and 1 square side is the radius of the half-circles. Since there are two half-circles, find the circumference for one full circle:

$C=2\pi r$

Insert the radius:

$r=10\\C=2\pi *10$

Simplify pi:

$C=2*3.14*10$

Simplify multiplication:

$C=6.28*10\\C=62.8$

The circumference of the circles is 62.8. Now find the perimeter of the exposed squares with side length 10. There are 4 exposed sides, which equals one square. Find the perimeter:

$P=10+10+10+10\\P=10+10+20\\P=10+30\\P=40$

Add the perimeter of the circle and the square together:

$P=62.8+40=102.8$

Now see which of the options gives you the perimeter:

1. $40+20\pi =102.8$ ****

2. $unavailable$

3. $120+20\pi =182.8$

4. $300+100\pi =614.2$

5. $10+10+10\pi +10+10+10\pi =102.8$ ****

Finito.

7 0

3 years ago

Help please! I've never been good at percents

Igoryamba

Answer:

the answer is: 64.9 but I'm not sure

5 0

3 years ago

Find the missing coefficient. - y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0

maria [59]

There is only one solution in the given equation -y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0. In solving this problem, apply first PEMDAS (parenthesis, exponents,multiplication, division, addition, subtraction). Then equation will transform into -y2+5y-7y2-9y+15y2+4y=0. Combine terms with same power and achieve 7y2=0. Divide both sides with 7 and perform square root of zero. Since the root is zero, we have one solution of the given equation which is y=0.

5 0

3 years ago

Read 2 more answers

Plz it’s for my finals!!

Mrac [35]

Pretty sure it would be D

Good luck on your finals!

3 0

3 years ago

What is 283+t 748-235+7493-7

WARRIOR [948]

Answer:

t^748+7534