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3 years ago

Which organisms are secondary consumers in a temperate coniferous forest? (Select all that apply.)

Chemistry

2 answers:

PIT_PIT [208]3 years ago

8 0

Answer:

wolf

Explanation:

kjhidyaU9Onjbhiojnld

Viktor [21]3 years ago

8 0

Wolf I learned this last year

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2Al2O3 → 4Al + 302

Anuta_ua [19.1K]

540g

Explanation:

Given parameters:

Mass of the aluminium oxide = 1020g

Unknown:

Mass of aluminium = ?

Solution:

To find the mass of the aluminium formed from this reaction, we work from the known to the unknown. The known here is the mass of the aluminium oxide.

Using this mass, find the number of moles in the aluminium and relate it using the balanced equation to that of the unknown aluminium.

From the number of moles, we can easily find the mass of the aluminium.

Solving:

Balanced equation:

2Al₂O₃ → 4Al + 3O₂

Number of moles of Al₂O₃ = $\frac{mass}{molar mass}$

Molar mass of Al₂O₃ = 2(27) + 3(16) = 102g/mol

Number of moles = $\frac{1020}{102}$ = 10mol

From the balanced equation:

2 moles of Al₂O₃ produced 4 moles of Al

10 moles of Al will produce $\frac{4 x 10}{2}$ = 20moles of Al

Mass of Al = number of moles of Al x molar mass of Al = 20 x 27 = 540g

Learn more:

Number of moles brainly.com/question/13064292

#learnwithBrainly

8 0

4 years ago

What substance is combination of different atoms

Furkat [3]

The substance which is a combination of different atoms is a compound.

7 0

3 years ago

Read 2 more answers

PROJECT: KITCHEN TOOLS

docker41 [41]

Answer:

Explanation:2+2=4

7 0

4 years ago

Question 2 of 5

Nataly_w [17]

Answer:

Explanation:

The answer is C because machines such as tractors and sprinklers are counted as technology, and are better examples than pesticides.

5 0

3 years ago

The molar solubilities of the following compounds (in mol/L) are:

IceJOKER [234]

Answer: The decreasing order of $K_{sp}$ is $AgSCN>AgBr>AgCN$

Explanation:

For AgBr:

The balanced equilibrium reaction for the ionization of silver bromide follows:

$AgBr\rightleftharpoons Ag^{+}+Br^-$

s s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ag^{+}][Br^-]$

We are given:

$s=7.3\times 10^{-7}mol/L$

Putting values in above equation, we get:

$K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(7.3\times 10{-7})^2=5.33\times 10^{-13}$

Solubility product of AgBr = $5.33\times 10^{-13}$

For AgCN:

The balanced equilibrium reaction for the ionization of silver cyanide follows:

$AgCN\rightleftharpoons Ag^{+}+CN^-$

s s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ag^{+}][CN^-]$

We are given:

$s=7.7\times 10^{-9}mol/L$

Putting values in above equation, we get:

$K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(7.7\times 10{-9})^2=5.93\times 10^{-17}$

Solubility product of AgCN = $5.33\times 10^{-17}$

For AgSCN:

The balanced equilibrium reaction for the ionization of silver thiocyanate follows:

$AgSCN\rightleftharpoons Ag^{+}+SCN^-$

s s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ag^{+}][SCN^-]$

We are given:

$s=1.0\times 10^{-6}mol/L$

Putting values in above equation, we get:

$K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(1.0\times 10{-6})^2=1.0\times 10^{-12}$

Solubility product of AgSCN = $1.0\times 10^{-12}$

The decreasing order of $K_{sp}$ follows:

$AgSCN>AgBr>AgCN$

4 0

4 years ago