Answer:
87.3 calories of heat is required.
Explanation:
Heat = mcΔT
m= mass, c = specific heat of silver, T = temperature
H= 57.8 g * 0.057 cal/g°C * ( 43.5 - 17 °C)
H = 57.8 * 0.057 * 26.5
H = 87.3069 cal.
The heat required to raise the temperature of 57.8 g of silver from 17 °C to 43.5 °C is 87.3 calories.
HCl is the limiting reactant, and 3.5 mol H2<span> can be formed</span>
Sulphate ion is used but fornyour kind information there ain't no place
Answer:
B, H, E, G, C, D, A, F
Explanation:
The ones closest to the bottom are the oldest
