Answer:
b Different amounts of food samples were used.
Explanation:
The mass of the two samples needs to be the same in order for the test to be accurate.
This doesn’t have a multiple choice part to answer.
It is in period 3
It is in group 17
It is a chlorine atom because it has 17 electrons which means the atomic number is 17
Answer:
![T_F=77.4\°C](https://tex.z-dn.net/?f=T_F%3D77.4%5C%C2%B0C)
Explanation:
Hello there!
In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:
![Q_1=-Q_2](https://tex.z-dn.net/?f=Q_1%3D-Q_2)
In terms of mass, specific heat and temperature change is:
![m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)](https://tex.z-dn.net/?f=m_1C_1%28T_F-T_1%29%3D-m_2C_2%28T_F-T_2%29)
Now, solve for the final temperature, as follows:
![T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}](https://tex.z-dn.net/?f=T_F%3D%5Cfrac%7Bm_1C_1T_1%2Bm_2C_2T_2%7D%7Bm_1C_1%2Bm_2C_2%7D)
Then, plug in the masses, specific heat and temperatures to obtain:
![T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C](https://tex.z-dn.net/?f=T_F%3D%5Cfrac%7B760g%2A0.87%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%20%2A52.2%5C%C2%B0C%2B70.7g%2A3.071%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%2A154%5C%C2%B0C%7D%7B760g%2A0.87%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%20%2B70.7g%2A3.071%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%7D%20%5C%5C%5C%5CT_F%3D77.4%5C%C2%B0C)
Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.
Regards!
Answer:
A. The ratio of the element in glucose is different than in ethanol
Explanation:
The compounds given are;
Glucose C₆H₁₂O₆
Ethanol C₂H₆O
The two compounds given are different from one another. But they have the same elemental composition.
Ethanol is made up of Carbon, hydrogen and Oxygen and so also, Glucose
Now,
The number of atoms in both compounds are different;
Number of atoms
C H O
Glucose 6 12 6
Ethanol 2 6 1