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Natali [406]
3 years ago
9

I. Escribe el tipo de reacción al que pertenece cada una de las siguientes reacciones: a. P4(s) + 3 O2 (g) → 2 P2O3 (g) b. CaCO3

(s) → CaO (s) + CO2 (g) c. Cu (s) + AgNO3 (ac) → CuNO4 (ac) + Ag (s) d. Pb(NO3)2 (ac) + NaI (ac) → PbI2 (s) + 2 NaNO3 (ac) e. FeCl3 + 3 NH4(OH) → Fe(OH)3 + 3 NH4Cl f. N2 + 3 H2 → 2NH3 g. Zn + 2HCl → H2 + ZnCl2 h. 2HgO → 2Hg + O2 i. 2H2(g) + O2 → 2H2O(l) j. 2H2O(l) → 2H2(g) + O2(g) k. Mg(s) + Cu(NO3)2 (ac) → Mg(NO3)2 (ac) + Cu(s) l. 2Na + 2H2O – > 2NaOH + H2 m. H2O + CO2 – > H2CO3 n. 2KClO3 – > 2KCl + 3O2 o. NaCl + LiNO3 – > NaNO3 + LiCl
Chemistry
2 answers:
ValentinkaMS [17]3 years ago
5 0
Sorry that’s a lot of hard math
mario62 [17]3 years ago
4 0
AgNO3. Hope this helps!
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One of relatively few reactions that takes place directly between two solids at room temperature is <img src="https://tex.z-dn.n
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a) Ba(OH)₂.8H₂O(s) + <em>2 </em>NH₄SCN(s) → Ba(SCN)₂(s) +<em>10</em> H₂O(l) + <em>2</em> NH₃(g)

b) 3.14g must be added

Explanation:

a) For the reaction:

Ba(OH)₂.8H₂O(s) + NH₄SCN(s) → Ba(SCN)₂(s) + H₂O(l) + NH₃(g)

As you see, there are 8 moles of water in reactants and 2 moles of oxygen in octahydrate, thus, water moles must be 10:

Ba(OH)₂.8H₂O(s) + NH₄SCN(s) → Ba(SCN)₂(s) +<em>10</em> H₂O(l) + NH₃(g)

To balance hydrogens, the other coefficients are:

Ba(OH)₂.8H₂O(s) + <em>2 </em>NH₄SCN(s) → Ba(SCN)₂(s) +<em>10</em> H₂O(l) + <em>2</em> NH₃(g)

b) As you see in the balanced reaction, 1 mole of barium hydroxide octahydrate reacts with 2 moles of NH₄SCN. 6.5g of Ba(OH)₂.8H₂O are:

6.5 g × (1mol / 315.48g) =<em> 0.0206moles of  Ba(OH)₂.8H₂O</em>. Thus, moles of NH₄SCN that must be used for a complete reaction are:

0.0206moles of  Ba(OH)₂.8H₂O × ( 2 mol NH₄SCN / 1 mol Ba(OH)₂.8H₂O) = <em>0.0412moles of NH₄SCN</em>. In grams:

0.0412moles of NH₄SCN × ( 76.12g / 1mol) = <em>3.14g must be added</em>

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