Find the common ratio for the following sequence. 27, 9, 3, 1, ... = 1/3
Find the common ratio for the following sequence. 1/2, -1/4, 1/8, -1/16, ... = -1/2
Find the common ratio for the following sequence. 1/2, -1/4, 1/8, -1/16, ...
= -1/2
Answer:
0.25
Step-by-step explanation:
0.52 is like 2 quarters
0.25 is 1 quarter
So, 1 < 2
Have a nice day! :)
Answer:
Problem 1. <em>(19/2)b + 15</em>
Problem 2. <em>3/16</em>
Step-by-step explanation:
Question number 1
5/8 (16b+24) -1/2b =
= (5/8) * (16/1) * b + (5/8) * 24 - (1/2)b
= 10b + 15 - (1/2)b
= (20/2)b - (1/2)b + 15
= (19/2)b + 15
Question number 2
3/4 (16/64 + 12a) -9a =
= (3/4) * (16/64) + (3/4) * 12a - 9a
= (3 * 16)(4 * 64) + (3/4) * (12/1) * a - 9a
= (3 * 1)(4 * 4) + (3 * 12)/(4 * 1) * a - 9a
= 3/16 + (3 * 3)/(1 * 1) * a - 9a
= 3/16 + 9a - 9a
= 3/16
Answer:
t = 9.57
Step-by-step explanation:
We can use trig functions to solve for the t
Recall the 3 main trig ratios
Sin = opposite / hypotenuse
Cos = adjacent / hypotenuse
Tan = opposite / adjacent.
( note hypotenuse = longest side , opposite = side opposite of angle and adjacent = other side )
We are given an angle as well as its opposite side length ( which has a measure of 18 ) and we need to find its adjacent "t"
When dealing with the opposite and adjacent we use trig ratio tan.
Tan = opp / adj
angle measure = 62 , opposite side length = 18 and adjacent = t
Tan(62) = 18/t
we now solve for t
Tan(62) = 18/t
multiply both sides by t
Tan(62)t = 18
divide both sides by tan(62)
t = 18/tan(62)
t = 9.57
And we are done!
Not entirely sure, but it seem the answer could be B.) It will not be spread out vertically across the entire coordinate plane because in step 5, Nancy selected an incorrect scale on the y-axis.
