Ask question

Ask question

All categories

1 year ago

9

Slove this please

t{15n^2} *\sqrt{10n^3}" alt="\sqrt{15n^2} *\sqrt{10n^3}" align="absmiddle" class="latex-formula">

1 answer:

larisa [96]1 year ago

4 0

Answer:

$5n^2\sqrt{6n}$

Start by breaking the radicand into assumed positive values. $15n - 10n = 5n^3$

$3+2 = 6$

Simplify.

$5n^2\sqrt{6n}$

You might be interested in

50 POINTS!!!!!!!

sesenic [268]

Answer:

Step-by-step explanation:

Part A: 4x^3y is a common variable

Part B: I found the common factor by looking at a common factor of the coefficient and the I look at the lowest exponent of each and put them as a factor

Part C: 4x^3y(9xy^2-4)

Hopes this helps please mark brainliest

5 0

1 year ago

A project has an initial cost of $60,000, expected net cash inflows of $14,000 per year for 9 years, and a cost of capital of 14

vredina [299]

Answer:

74

Step-by-step explanation:

60,000 + 14,000

ANS 14%

ANSWER: 74

6 0

3 years ago

To find the distance across a lake, a

Nesterboy [21]

The distance across the lake, a is 611 yards

<h3>Right angle triangle:</h3>

Right angle triangle have one of its angles as 90 degrees. Therefore, the side a can be found using trigonometric ratios,

Therefore,

tan 47° = opposite / adjacent

tan 47° = a / 570

cross multiply

a = 570 tan 47°

a = 570 × 1.07236871002

a = 611.250164714

a = 611 yards

learn more on right triangle here: brainly.com/question/18450490

6 0

2 years ago

Read 2 more answers

I WILLLL GIVE THE BRANLIEST HELPPP PLZZZLine the synonyms up in order from slow to slowest

GREYUIT [131]

Unhurried
Relaxed
Easy lagging
Eisurely

3 0

3 years ago

Read 2 more answers

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

3 years ago