When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)
Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12
By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.
Answer: b=12
Answer:
(a) ΔARS ≅ ΔAQT
Step-by-step explanation:
The theorem being used to show congruence is ASA. In one of the triangles, the angles are 1 and R, and the side between them is AR. The triangle containing those angles and that side is ΔARS.
In the other triangle, the angles are 3 and Q, and the side between them is AQ. The triangles containing those angles and that side is ΔAQT.
The desired congruence statement in Step 3 is ...
ΔARS ≅ ΔAQT
Answer: 3/5
Step-by-step explanation: Just divide both by 5.
The correct answer is 160%
5/5 = 100% and 3/5 = 60%, you can add the two together
Solve for x in first equation:
x-2y=7
Add “2y” to both sides
x=2y+7
Put this in to second equation:
3(2y+7)+2y=21
Solve for y:
Distribute the 3 into the ()
6y+21+2y=21
Combine the like y terms
8y+21=21
Subtract 21 from both sides
8y=0
Divide by 8 on both sides
y=0
Put this into the first solved equation:
x=2(0)+7
Solve for x:
Multiple 2(0)
x=0+7
Add 0 and 7
x=7
So the value of x is positive 7.
