Answer:
_______________________________________________
1)
72
cm² / min. ;
_______________________________________________
2)
192
cm² / min. _______________________________________________Explanation:____________________________________________ Area of a circle: A =

r² ;
Rate of change of Area is: da/dt = 2

r (dr/dt) ;
Given: dr/dt = 3 cm / min.
______________________________________________________ Problem 1)____________________________________________________________dA/dt = 2

*(12 cm)*(3 cm/ min) =
72
cm² / min. ;
____________________________________________________________ Problem 2)____________________________________________________________dA/dt = 2

*(32 cm)*(3 cm/ min) =
192
cm² / min._____________________________________________________________
To solve this, we divide 48 by 3.
48÷3=16
16 blocks per hour.
The correct answer is D.D. 8a^4b^3 + 6a^3b^5 - 2a^3b^4
You can tell this by the lead term alone. When you mutliply the term outside to the lead term, D is the only one that has that term.
2a^2b^3*4a^2 = 8a^4b^3
D. 8a^4b^3 + 6a^3b^5 - 2a^3b^4
The answers
1)-7
2)-1.5
3) 2
Yes 4/5 is greater than 1/3. Convert the fractions to the same denominator so 1/3 becomes 5/15 and 4/5 becomes 12/15. So 12/15 is more than 5/15.