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vfiekz [6]
3 years ago
12

Leo needs 10 red roses and 1515 pink daisies for every 5 bouquets he makes for a flower shop. Drag red roses and pink daisies in

to the box to show how many Leo needs for 3 bouquets.
Mathematics
2 answers:
harkovskaia [24]3 years ago
6 0
He needs 2 red roses and 303 pink daisies for 1 bouquet. So you multiply that by 3 and you get 6 red roses and 909 pink daisies.
Marina CMI [18]3 years ago
3 0
2 red roses per bouquet. 3 pink daisies are needed.
2•3=6
3•3=9
9+6=15
he needs 6 roses and 9 daisies.
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Determine whether the sequence is geometric. If so, find the common ratio. 3.0, 6.0, 12.0, 24.0
Luba_88 [7]

Answer:

The sequence <u>is</u> geometric and the common ratio is 2

Step-by-step explanation:

A sequence is geometric if each term  (after the first one) is equal to the term before it times some constant number, called the 'common ratio'.

Examples:  1, 2, 4, 8, 16, ... has a common ratio of 2 because 2*2 = 4, and 4*2 = 8, and so on.

                 Also, -->  4, 2, 1, 1/2, 1/4/ 1/8, ... has a common ratio of 1/2 because

4 * 1/2 =  the next term 2, and 2 * 1/2 = the next trem 1/4, and son on.

In this case, 3 * 2 = 6

                    6 * 2 = 12

                    12 * 2 = 24

The sequence <u>is</u> geometric and the common ratio is 2

6 0
2 years ago
Complete the chart to find the mean, variance, and standard deviation. Remember to use commas and round numbers to the nearest t
vitfil [10]

Answer: The mean of the data is 433.75, variance of the data is 99667.19 and the standard deviation of the data is 315.7011.

Explanation:

The given data is 900, 35, 500 and 300.

The number of observation is 4.

Formula of mean is,

\text{Mean}=\frac{\text{Sum of observations}}{\text{Number of observations}}

\bar{X}=\frac{900+35+50+300}{4} =433.75

The formula of variance is given below,

\sigma^2=\frac{1}{n}\sum{(X-\bar{X})^2}

\sigma^2=\frac{398668.75}{4}

\sigma^2=99667.19

The variance of the data is 99667.19

\sigma=\sqrt{99667.19}

\sigma=315.7011

The standard deviation of the data is 315.7011.

The other information or values of given chart is shown in the attached table.

8 0
3 years ago
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Which of the following equations has no solution?
liubo4ka [24]

Answer:

the last one

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3 0
3 years ago
The sale bin in a clothing store contains an assortment of t-shirts in different sizes. There are 7 small, 8 medium, and 4 large
umka21 [38]

Answer:

P(at least 1 large) = 0.648

P(at least 1 large) = 64.8%

Step-by-step explanation:

We have 7 small shirts, 8 medium shirts and 4 large shirts

Total number of shirts = 7 + 8 + 4 = 19 shirts

The probability that at least one of the first four shirts he checks is a large is given by

P(at least 1 large) = 1 - P(no large)

So first we need to find the probability that the none of the first four shirts he checks are large.

For the first check, there are 15 small and medium shirts and total 19 shirts so,

15/19

For the second check, there are 14 small and medium shirts and total 18 shirts left so,

14/18

For the third check, there are 13 small and medium shirts and total 17 shirts left so,

13/17

For the forth check, there are 12 small and medium shirts and total 16 shirts left so,

12/16

the probability of not finding the large shirt is,

P(no large) = 15/19*14/18*13/17*12/16

P(no large) = 0.352

Therefore, the probability of finding at least one large shirt is,

P(at least 1 large) = 1 - P(no large)

P(at least 1 large) = 1 - 0.352

P(at least 1 large) = 0.648

P(at least 1 large) = 64.8%

4 0
2 years ago
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