Answer:
t≥2
Step-by-step explanation:
because you need at least 2 touchdowns, t must be equal to 2 or more (greater) than 2.
Answer:
The minimum score required for an A grade is 83.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 72.3 and a standard deviation of 8.
This means that 
Find the minimum score required for an A grade.
This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.




The minimum score required for an A grade is 83.
The transformation is done to y=1/x to get y=1/4x-12. We defined a turning point in the equation which will indicate the point in the graph.
We changed the form from y=x to y=x+c. In this case, we use 1/2 for the and constant C value which is -12.
y = florida's number of countries x = countries in Arizona
y=5x-8