Answer:
no solution
Step-by-step explanation:
For getting the nature of solution of the quadratic equation of the form:
ax² + bx + c = 0
We need to find Discriminant which is:
Discriminant (D) = b² - 4ac
- If D < 0, there is no solution of equation.
- If D = 0, there are two equal and real solution of equation
- If D < 0, there are two real and distinct solution of equation
Here we have equation is:
2x² - 9x + 12 = 0
∴ a=2, b = -9, c = 12
⇒ D = 81 - 4 × 2 × 12 = -16 < 0
Hence, there is no solution of given equation.
X+(x+1)+(x+2)+(x+3)=156
4x+6=156
4x=150
x=37.5 (not an integer)
If x=37 you get 37+38+39+40=154 and if x=38 you get 38+39+40+41=158[/tex]
uh idk um...
Okay well to answer this you have to work the problem out and enable to do that you have to look at the information provided, also STOP CHEATING AND FIGURE IT OUT
um i mean.....GOODLUCK!!!! I know you can do it :)
X = y + 12. You then substitute or plug in that from the first equation into the second equation. You get (y+12)+y=18, then you simplify to get your y value. In this case y = 3. The you can plug your y value into either equation. (x+3=18) or (x-3=12) or (x=3+12) either way you get x=15 and y=3.
<span>3p + 15 = 3(p + 5) (distributive property)
answer
</span><span>3(p + 5)</span>
