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pogonyaev
2 years ago
8

Find 4 consecutive even integers whose sum is 156?

Mathematics
2 answers:
snow_tiger [21]2 years ago
8 0
X+(x+1)+(x+2)+(x+3)=156
4x+6=156
4x=150
x=37.5 (not an integer)
If x=37 you get 37+38+39+40=154 and if x=38 you get 38+39+40+41=158[/tex]
sergejj [24]2 years ago
3 0

Answer: The integers are 36, 38, 40, and 42

Step-by-step explanation:

156/2=78

Find even integers by dividing that by two. 39.

So the two middle integers are 38 and 40.

You can go from there.

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3 years ago
For the rhombus below, find the measure of angles 1,2,3 and 4.
Alexus [3.1K]

Answer:

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Step-by-step explanation:

First off, we already know that ∠2 is 57° because of alternate interior angles.

Second, it's important to know that rhombus' diagonals bisect each other; meaning they form 90° angles in the intersection. Another cool thing is that the diagonals bisect the existing angles in the rhombus. Therefore, 57° is just half of something.

Then, you basically just do some other pain-in-the-butt things after.

Since that ∠2 is just the bisected half from one existing angle, that means that ∠3 is just the other half; meaning that ∠3 is 57°, as well.

Next is to just find the missing angle ∠1. Since we already know ∠3 is 57°, we can just add that to the 90° that the diagonals formed at the intersection.

57° + 90° = 147°

180° - 147° = 33°

∠1 is 33°

Finally, since that ∠4 is just an alternate interior angle of ∠1, ∠4 is 33°, too.

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Read 2 more answers
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