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Fynjy0 [20]
3 years ago
10

Please include work! :)

Mathematics
1 answer:
UNO [17]3 years ago
6 0

Answer:

m = 13.

Step-by-step explanation:

Recall that adding logarithmic equations, (ex: log a + log b) is the same as log (a·b). Therefore:

log 12 + log 5 = log (4m + 8)

log (12·5) = log (4m + 8)

log (60) = log (4m + 8)  **Ignore 'Log' to solve for 'm'

60 = 4m + 8  **Subtract both sides by 8

52 = 4m  **Divide both sides by 4

m = 13.

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Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let <em>x</em> be the inverse. Then <em>x</em> is such that

23<em>x</em> ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for <em>x</em> :

1000 = 43×23 + 11

23 = 2×11 + 1

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→   1 ≡ 87×23 - 2×1000 ≡ 87×23   (mod 1000)

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3 years ago
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Step-by-step explanation:

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Answer:

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