Answer: ummm i think it's -1
Step-by-step explanation:
Answer:
Maybe 3 1/2 but they don't give enough information
Just for you beautiful!
Use distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
(11,-4) is (x1,y1) and (-12,-4) is (x2,y2)
Plug in and simplify
d = sqrt((-12 - 11)^2 + (-4 - -4)^2)
d = sqrt((-23)^2 + (0)^2)
d = sqrt(529 + 0)
d = sqrt(529)
d = 23 (positive because length cannot be negative) ;)
Answer:
V(X)= 39.10
V(Y)= 40
Step-by-step explanation:
Given that
Total number of student = 140
Bus A - 31
Bus B- 43
Bus C- 27
Bus D- 39
The probability that a student was on the bus is proportional to the number of student. Eg 31/140 in bus A, 43/140 on bus B, ...
E(X) = (31*31/140) + (43*43/140) + (27*27/140) + (39*39/140)
= 35.5

V(X)= 39.10
The bus driver have 1/4 probability on being on any of the buses.
E(Y) = 140/4 = 35

V(Y)= 40
This is a Pythagorean Theorem problem. 3^2 + 7^2 = 58. C^2 = 58. C = 7.6157 (exact)
There is no exact answer for this. The closest we can get to 58 is 7.6157, which would leave us at 57.9988. So the approximate value is 7.6, but if you need the closest answer, it’s 7.6157.