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3 years ago

12

Heather's fish tank has 18 liters of water in it. she plans to add 4 liters per minute until the tank has more than 58 liters. w

hat are the possible numbers of minutes heather could add water?

1 answer:

Volgvan3 years ago

3 0

It tank will be filled up in 40 mins cause every min you fill in 4 liters. Don’t take my word for this make sure you check my work.

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In a right triangle one acute angle measures 48 more than 2 times the other. If the sum of the measure of the two acute angles m

Ainat [17]

A given angle measures 90°.. Then, note that the total measurement of the triangle is 180°... Subtract 180° by 90°, and the other angles must add up to 90°!

Good luck!

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3 years ago

For the cost function c equals 0.1 q squared plus 2.1 q plus 8, how fast does c change with respect to q when q equals 11? Det

Soloha48 [4]

Answer:

Rate of change of c with respect to q is 4.3

Percentage rate of change c with respect to q is 9.95%

Step-by-step explanation:

Cost function is given as, $c=0.1\:q^{2}+2.1\:q+8$

Given that c changes with respect to q that is, $\dfrac{dc}{dq}$ . So differentiating given function,

$\dfrac{dc}{dq}=\dfrac{d}{dq}\left (0.1\:q^{2}+2.1\:q+8 \right)$

Applying sum rule of derivative,

$\dfrac{dc}{dq}=\dfrac{d}{dq}\left(0.1\:q^{2}\right)+\dfrac{d}{dq}\left(2.1\:q\right)+\dfrac{d}{dq}\left(8\right)$

Applying power rule and constant rule of derivative,

$\dfrac{dc}{dt}=0.1\left(2\:q^{2-1}\right)+2.1\left(1\right)+0$

$\dfrac{dc}{dt}=0.1\left(2\:q\right)+2.1$

$\dfrac{dc}{dt}=0.2\left(q\right)+2.1$

Substituting the value of $q=11$ ,

$\dfrac{dc}{dt}=0.2\left(11\right)+21.$

$\dfrac{dc}{dt}=2.2+2.1$

$\dfrac{dc}{dt}=4.3$

Rate of change of c with respect to q is 4.3

Formula for percentage rate of change is given as,

$Percentage\:rate\:of\:change=\dfrac{Q'\left(x\right)}{Q\left(x\right)}\times 100$

Rewriting in terms of cost C,

$Percentage\:rate\:of\:change=\dfrac{C'\left(q\right)}{C\left(q\right)}\times 100$

Calculating value of $C\left(q \right)$

$C\left(q\right)=0.1\:q^{2}+2.1\:q+8$

Substituting the value of $q=11$ ,

$C\left(q\right)=0.1\left(11\right)^{2}+2.1\left(11\right)+8$

$C\left(q\right)=0.1\left(121\right)+23.1+8$

$C\left(q\right)=12.1+23.1+8$

$C\left(q\right)=43.2$

Now using the formula for percentage,

$Percentage\:rate\:of\:change=\dfrac{4.3}{43.2}\times 100$

$Percentage\:rate\:of\:change=0.0995\times 100$

$Percentage\:rate\:of\:change=9.95%$

Percentage rate of change of c with respect to q is 9.95%

7 0

3 years ago

4+2×1+3? How do u solve this please?

Bad White [126]

Answer:

7

Step-by-step explanation:

PEMDAS multiply 2 times 1 then add 4 and 3

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3 years ago

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2/3 x (-6/7 + 4/5) = (2/3 x 4/5) x (-6/7) : verify

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⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✿⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎

Hi my lil bunny!

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Let's solve your equation step-by-step.

$(\frac{2}{3}x) ( \frac{-6}{7} + \frac{4}{5}) = [\frac{\frac{2^x4}{3} }{5} ] ( \frac{-6}{7} )$

$\frac{-4}{105} x = \frac{-4x^5}{35}$

Step 1: Subtract $(-4)/35x^5$ from both sides.

$\frac{-4}{105} x - \frac{-4}{35x^5} = \frac{-4x^5}{35} - \frac{-4x^5}{35}\\\\\frac{4}{35}x^5 + \frac{-4}{105} = 0$

Step 2: Factor left side of equation.

$x(0.114286 x^4 - 0.038095 ) = 0$

Step 3: Set factors equal to 0.

$x = 0 or 0.114286 x^4 - 0.038095 = 0\\\\x = 0 or x = -0.759836 or x = 0.759836$

So the answer is : x = 0 or x = - 0.759836 or x = 0.759836

❀ _____.______❀_______._____ ❀

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Hope this helped you.

Could you maybe give brainliest..?

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3 years ago

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The corporate team-building event will cost $8 if it has 4 attendees. How many attendees can

sukhopar [10]

Answer: 22 attendees can attend the corporate team-building event, with a budget of $46.

1. 8 = 4x
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4 years ago