1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
harkovskaia [24]
3 years ago
9

Calculate the minimum number of subjects needed for a research study regarding the proportion of respondents who reported a hist

ory of diabetes using the following criteria:
95% confidence, within 5 percentage points, and a previous estimate is not known.
Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:

The minimum number of subjects needed is 385.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

95% confidence, within 5 percentage points, and a previous estimate is not known.

The sample size is n for which M = 0.05. We don't know the true proportion, so we use \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.05 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.05\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.05}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.05})^2

n = 384.16

Rounding up:

The minimum number of subjects needed is 385.

You might be interested in
Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born
NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of a person being in May:

May has 31 days in a year of 365. So

p = \frac{31}{365} = 0.0849

Group of 20 friends:

This means that n = 20

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

3 0
3 years ago
Given: O ∈ AB , ON is ∠ bisector of ∠AOC, OF is ∠ bisector of ∠COB, m∠FOB=70°. Find: m∠AON
Julli [10]

Answer:

AOC = 20 degrees

Step-by-step explanation:

We know that FOB is 70 degrees, and COF is 90 degrees. So just add 70+90 and get 160 degrees. Then you subtract that from AOB which is 20 degrees.

5 0
3 years ago
Suppose two random variables, X and Y are independent, which statement is false? a) P(X∣Y)=P(X) b) P(X∪Y)=P(X)+P(Y) c) P(X∩Y)=P(
Svetlanka [38]

B is false, since by the inclusion/exclusion principle,

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)

By independence, we have P(X\cap Y)=P(X)P(Y), which is zero if either of P(X) or P(Y) is 0, which isn't guaranteed.

5 0
3 years ago
What is the perimeter of a regular heptagon with a side length of 9 inches?
jok3333 [9.3K]
What kind of Question is that. That is some real math right there.
6 0
3 years ago
How t f do I lable this I get so many of these and I've never been thought it
Naddika [18.5K]

Answer:

Label the y-axis Charms and the x-axis Beads

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • Complete the table <br> | 2 | 5 | | 28 |<br> |6.5| |39| |
    12·1 answer
  • A store is mixing peanuts, which cost $3.20 per pound, and raisins, which cost $2.10 per pound.
    7·2 answers
  • A florist has 30 carnations and 42 roses. He wants to put the flowers in vases so that each vase has the same number of flowers
    12·1 answer
  • Help with the posted question
    8·2 answers
  • Multiply Using Two-Digit Numbers Look at the problem 325 x 89. 1. Write out the six multiplication problems that are involved in
    10·1 answer
  • Divison i need help with that
    13·1 answer
  • Find the sum (1−5q)+2(2.5q+8) =
    14·2 answers
  • Your paycheck from work was $304.25. You used some of your earnings to buy an MP3 player for $149. Now it will cost you $1.15 to
    11·2 answers
  • The formula to find the area of a triangle is:
    6·1 answer
  • Hellllllllllllllllllllppppppppppppp me extra point
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!