Express the revenue equation in terms of price given the demand function.

Solve the simultaneous equation x2+y2= 26 X - Y = 4

gayaneshka [121]

The answer is X=1, y=5. X=-5 y=-1

5 0

3 years ago

Which equation is the inverse of 2(x - 2)2 = 8(7 + y)?

Temka [501]

The answer to your question is D.

4 0

2 years ago

Point A is at (2, -8) and point C is at (-4, 7).

Dahasolnce [82]

Answer:

(-2, 2)

Step-by-step explanation:

Given:

Point A is at (2, -8) and point C is at (-4, 7)

Difference of coordinates:

Δx = 2 - (-4) = 6
Δy = - 8 - 7 = - 15

The ratio of AB to AC is 2:1. So:

AB = 2*AC/3 and BC = AC/3

Then coordinates of point B should be 2/3 from the point A:

x = 2- 6*2/3 = 2 - 4 = -2
y = - 8 - (-15)*2/3 = -8 + 10 = 2

So point B has coordinates of (-2, 2)

7 0

3 years ago

EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of

saw5 [17]

Answer: (a) 0.006

(b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

= P(AA) x P(D/AA)

= 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

= 0.3(0.02) + 0.70(0.03)

= 0.027

3 0

3 years ago

Y=4x-6 and passes through point 8,12

umka2103 [35]

Answer:

Slope of required line if both lines are parallel: y=4x-20

Slope of required line if both lines are perpendicular: y=-1/4x+14

Step-by-step explanation:

We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)

Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.

If Both lines are parallel the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are parallel there slopes are same

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=4

Now finding y-intercept

Using slope m=4 and point (8,12) we can find y-intercept

$y=mx+b\\12=4(8)+b\\12=32+b\\b=12-32\\b=-20$

y-intercept of new line is: b=-20

Equation of required line having slope m=4 and y-intercept b=-20 is

$y=mx+b\\y=4x-20$

If Both lines are perpendicular the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are perpendicular there slopes are opposite of each other

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=-1/4

Now finding y-intercept

Using slope m=-1/4 and point (8,12) we can find y-intercept

$y=mx+b\\12=-\frac{1}{4} (8)+b\\12=-2+b\\b=12+2\\b=14$

y-intercept of new line is: b=14

Equation of required line having slope m=-1/4 and y-intercept b=14 is

$y=mx+b\\y=-\frac{1}{4} x+14$

8 0

2 years ago