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3 years ago

Express the revenue equation in terms of price given the demand function.

Mathematics

1 answer:

statuscvo [17]3 years ago

4 0

Answer:

Step-by-step explanation:

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Trevor performed an experiment in which he randomly pulled a card from a standard deck, recorded the card's value, returned the

Alika [10]

Ansi dont know

Step-by-step explanation:

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2 years ago

Find a b if a = (4,3) and b =(4,5).<br> a. 31<br> C. (16,15)<br> b. (8,8)<br> d.-1

liq [111]

Your answer will be c

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3 years ago

Read 2 more answers

One half of the sum of a number and 10

garri49 [273]

Let's assume the number be x.

So, sum of a number and 10 can be written as x+10.

Now the given statement is "One half of the sum of a number and 10 ".

So, one half of x+10 can be written as $\frac{1}{2} (x+10)$

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3 years ago

Safiya deposited money into a bank account that earned 6.5% simple interest each year. After 3 1/2 years, she had earned $36.40

N76 [4]

Answer:

$1,792

Step-by-step explanation:

3 1/2×36.40=116.48

116.48÷6.5%=1,792

$1,792

5 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago