x/y + 3z^2 for x= 2/3, y= 6/7, and z=3
=2/3 / 6/7 + 3(3^2)
=2/3 * 7/6 + 3(9)
= 7/9 + 27
= 7/9 + 243/9
= 250/9
answer is a. 250/9
Answer:
x<1
Step-by-step explanation:
2x+2<2(3x-1)
2x+2<6x-2
2x<6x-4
-4x<-4
x<1
As an improper fraction, it would be -11/4
As a mixed number, it would be
-2 and 3/4
Answer:
Solution : Volume = 96/5π
Step-by-step explanation:
If we slice at an arbitrary height y, we get a circular disk with radius x, where x = y^(1/3). So the area of a cross section through y should be:
A(y) = πx^2 = π(y^(1/3))^2 = πy^(2/3)
And now since the solid lies between y = 0, and y = 8, it's volume should be:
V = ∫⁸₀ A(y)dy (in other words ∫ A(y)dy on the interval [0 to 8])
=> π ∫⁸₀ y^(2/3)dy
=> π[3/5 * y^(5/3)]⁸₀
=> 3/5π(³√8)⁵
=> 3/5π2^5
=> 96/5π ✓
