Given:
114.32g of water
14.85oC is raised
to 18.00oC
Required:
Change in heat
energy
Solution:
This can be solved
through the equation H = mCpT
where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
The specific heat
of the water is 4.18 J/g-K
Plugging in the
values into the equation
H = mCpT
H = (114.32g) (4.18
J/g °C) (18 – 14.85)
H = 1,505.3 J
Answer: Diatomic molecules are molecules made of two atoms chemically bonded together.
Answer : The specific heat of the metal is,
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of water =
= mass of metal = 75 g
= mass of water =
= final temperature of mixture =
= initial temperature of metal =
= initial temperature of water =
Now put all the given values in the above formula, we get
Therefore, the specific heat of the metal is,