As one element .because po4 is phosphate for e.g.: NaPO4
Answer:
B. use a new pair of gloves for each piece of evidence
Explanation:
When it comes to the basic precautions of handling biological evidence samples, one has to prevent cross contamination. This refers to the<em> transfer of DNA from one evidence to another evidence</em>; thus, it is important for Jane to use a new pair of gloves for each piece of evidence in order to prevent such occurrence.
Wearing of gloves will also <em>prevent Jane's DNA from being implanted into the sample</em>, and it will keep her safe from contracting blood-borne pathogens like those in the saliva, blood or semen.
Answer:
11.2 M → [HCl]
Explanation:
Solution density = Solution mass / Solution volume
35.38 % by mass, is the same to say 35.38 g of solute in 100 g of solution.
Let's determine the moles of our solute, HCl
35.38 g . 1 mol/36.45 g = 0.970 moles
Let's replace the data in solution density formula
1.161 g/mL = 100 g / Solution volume
Solution volume = 100 g / 1.161 g/mL → 86.1 mL
Let's convert the volume to L → 86.1 mL . 1L / 1000 mL = 0.0861 L
Molarity (M) → mol/L = 0.970 mol / 0.0861 L → 11.2 M
<h3>
Answer:</h3>
7.226 × 10^23 molecules.
<h3>
Explanation:</h3>
- A compound is a substance that is made by two or more atoms from different elements.
- A mole of a compound contains a number of molecules equivalent to Avogadro's number, 6.022 × 10^23.
- That is, one mole of a compound contains 6.022 × 10^23 molecules.
In this case we are given;
Number of moles of H₂O as 1.2 moles
But, 1 mole of H₂O contains 6.022 × 10^23 molecules.
We are required to calculate the number of molecules present;
- To calculate the number of molecules we are going to multiply the number of molecules in one mole by the number of moles.
Number of molecules = 1.2 moles × 6.022 × 10^23 molecules/mole
= 7.226 × 10^23 molecules.
Thus, 1.2 moles of water contains 7.226 × 10^23 molecules.
The answer is <span>the
reaction will shift to the left (toward the reactants).
Reaction is at equilibrium can be expressed as,
Reactants </span>⇄ products<span>
<span>After coming to the equilibrium, if one condition
is changed, then according to the </span>Le chatelier's Principal,<span> the system
will act to maintain the equilibrium by reducing the effect. As an example, if
we reduce the pressure, then system acts to increase the pressure to maintain
the equilibrium.</span>
<span>Likewise, if we add products into the reaction
which is in equilibrium, the system acts to reduce the effect by promoting the backward
reaction to produce reactants.</span></span>
