Colorful flowers and blueberrie looking ones and the trees
A neutral atom in its ground state contains 28 electrons. this element is considered a <span>transition </span>element, and has 8 electrons in orbitals with l = 2.
Electron configuration: ₂₈X 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁸ 4s².
l is azimuthal quantum number, l = 2 describes d orbital. There is eight electrons in 3d orbital.
2.07 M is the molarity of the final solution if 45.0 ml of 6.00M HCl is added to 130 ml of
O.
Explanation:
Data given:
volume of HCl, V1 = 45 ml
molarity of the HCl solution, M1 = 6 M
final volume of the HCl solution after water is added, V2 = 130 ml
final molarity M2 =?
After the dilution, the molarity of the new solution can be found by using the formula:
M1V1 = M2V2
here M1 and V1 are the molarity and volume for concentrated solution, M2 and V2 represents the diluted solution's molarity and volume.
Applying the formula after rearranging the equation, we get
M2 = 
M2 = 
M2 = 2.07 M
The final molarity of the HCl solution is 2.07 M
Answer:
about 327 g of sulfur
Explanation:
Reaction equations.
2S + 2O2 = 2SO2
2SO2 + O2 = 2SO3
2SO3 + 2H2O = 2H2SO4
1.00 kg H2SO4 (1000 g H2SO4 / 1kg H2SO4) x (1 mole H2SO4 / 98.079 g H2SO4) x
(1 mole S / 1 mole H2SO4) x (32.065 g S / 1 mole S)
= 326.93 g S needed to be burned to produce 1.00 kg of H2SO4