(x^2-y^2)+(2x+2y)= (x+y).(x-y) +2.(x+y) = (x+y).(x-y+2)
Answer:
1. 20
2. 35
3. 20
4. 20
Step-by-step explanation:
Are u serious..... ඩඩඩඩඩඩඩ
Answer:
number of non students=140, students=280
Step-by-step explanation:
let non students be x.
so according to condition, non students=x*9
students=2x*7
now,
2x*7+x*9=3220
so, x=140
I'm assuming the two equations are as follows:
y = 5x
7x + 2y = -17
You can substitute 5x for y in the second equation since they are equivalent. Remember that whatever you do to one side you must do to the other as well.
7x + 2y = -17
7x + 2(5x) = -17
7x + 10x = -17
17x = -17
17x /17 = -17 /17
x = -1
Now we sub in the value we have for x to find y:
y = 5x
y = 5(-1)
y = -5
We now check that both answers are right by substituting them both into the second equation:
7x + 2y = -17
7(-1) + 2(-5) = -17
-7 + (-10) = -17
-17 = -17
And it looks like it works! So x = -1, and y = -5. Hope this helps! :)
Graphs of linear functions
Since we are graphing a line, if we have two points we can plot the whole line
We evaluate the line in two points in order to locate two places where it passes through. We say y = h(x)
1. If x = 0 then
h(x) = - 5(0) +3
= 0 + 3
= 3
Then y = 3
2. If x = 2 then
h(x) = - 5(2) +3
= -10 + 3
= -7
Then y = -7
Now, we have two points: (0, 3) and (2, -7)
We locate them and then we plot the only straight line that passes through both points