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ycow [4]
2 years ago
6

Item 5 Identify the terms, coefficients, and constants in the expression 6 + n x n + 1/2d

Mathematics
1 answer:
Alenkasestr [34]2 years ago
7 0

Answer:

Terms (Variables) =  x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6

Step-by-step explanation:

6 + n x n + 1/2d

6 + n^2 x + 1/2d

Terms (Variables) =  x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6

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Name a point that is between 50 and 60 units away from (7,-2) and state the distance between the two points.
laila [671]

Let the required point be (a,b)

The distance of (a,b) from (7,-2) is

= \sqrt{(a-7)^2+(b+2)^2}

But this distance needs to be betweem 50 & 60

So

50

Squaring all sides

2500 < (a-7)² + (b+2)² < 3600

Let a = 7

So we have

2500 < (b+2)² <3600

b+2 < 60    or  b+2 > -60   => b <58 or b > -62

Also

b+2 >50    or b + 2 < -50  => b >48 or B < -52

Let us take one value of b < 58 say b = 50

So now we have the point as (7, 50)

The other point is (7,-2)

Distance between them

= \sqrt{(7-7)^2+(50+2)^2}= \sqrt{(52)^2}=52

This is between 50 & 60

Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)


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3 years ago
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The answer should be 1.8 or 1 4/5
8 0
2 years ago
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Sauron [17]

Answer:

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muminat
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