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2 years ago

What is the experimental probability of a coin toss results in two heads showing?

Mathematics

2 answers:

lorasvet [3.4K]2 years ago

8 0

Answer:

1 in 4 chance

25% chance

Liono4ka [1.6K]2 years ago

6 0

Answer:

25%

(1/4.)

Step-by-step explanation:

So, to get heads twice in a row in two coin tosses it would be 25%. The odds of getting a heads with one coin toss is 50% (1/2.) Every time you do another coin toss the odds are halfed again. So half of 1/2 is 1/4 (think about it as like 50 divided by 2, so 25%.)

Hope this helps and have a nice day! Sorry I'm not great at explaining!

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1 year ago

Read 2 more answers

A golfer keeps track of his score for playing nine holes of golf (half a normal golf round). His mean score is 8080 with a sta

solniwko [45]

Answer:

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and $11\sqrt2$ respectively.

Step-by-step explanation:

Given that,

For the first 9 holes X:

E(X) = 80

SD(X)=13

For the second 9 holes Y:

E(Y) = 80

SD(Y)=13

For the sum W=X+Y, the following properties holds for means , variance and standard deviation :

E(W)=E(X)+E(Y)

and

V(W)=V(X)+V(Y)

⇒SD²(W)=SD²(X)+SD²(Y) [ Variance = (standard deviation)²]

$\Rightarrow SD(W)=\sqrt{SD^2(X)+SD^2(Y)}$

∴E(W)=E(X)+E(Y) = 80 +80=160

and

∴ $SD(W)=\sqrt{SD^2(X)+SD^2(Y)}$

$=\sqrt{11^2+11^2}$

$=\sqrt{2.11^2}$

$=11\sqrt2$

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and $11\sqrt2$ respectively.

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2 years ago

Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!

alexdok [17]

Answer:

See below

Step-by-step explanation:

Let the amount charged is y and number of hours is x.

Then the equations are as below.

Attorney A:

y = 150x + 250

Attorney B:

y = 175x + 150

If the amounts are equal, then:

150x + 250 = 175x + 150
175x - 150x = 250 - 150
25x = 100
x = 4 hours

3 0

1 year ago