The circumference would be 16.328 mm.
In one tray, we have 1/5. Since one is purple out of the 5 colors.
So in 20 trays, we have:
(1/5) x 20 = 20/5 = 4
Answer:
The number of weeks required = 216 weeks
Step-by-step explanation:
Given that:
Margin of Error E = 200
Confidence interval = 95% = 0.95
Level of SIgnificance = 1 - C.I
= 1 - 0.95
= 0.05
Standard deviation = 1500
The Critical value for Z :

The number of weeks( i.e the sample size (n) ) required is :



n = 216.09
n ≅ 216 weeks