How do you make a YBCO?

2 answers:

7 0

The easy way to make YBCO involves multiple rounds of pulverizing yttrium oxide, barium chloride carbonate, and copper oxide together and heating them in a furnace. That works, sort of, but [Ben] wanted more, so he performed a pyrophoric reaction instead.

FinnZ [79.3K]3 years ago

5 0

Answer:

Synthesis of a Superconductor. The YBa2Cu3O7-x is prepared by grinding the reactants together, strongly heating "calcinating" at 900–950 °C for 8-12 hours, pelletizing the powder mixture, heating or "sintering" the pellet at 950 °C for 12 or more hours, then maintaining the product at 500°C for 12-16 hours.

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My name is Ann [436]

Answer: Tfinal = 7.1°C

Explanation:

heat released or absorbed = mass × specific heat capacity × change in temperature

q = m × cg × ΔT (eqn 1)

Note: ΔT = (Tfinal - Tinitial)

(q = ? ΔHsoln=25.7kJ/mole = 25700J/mole; mass of solution, m = 100 + 35g = 135g; cg = specific heat capacity of water = 4.18 J°C-1g-1; ΔT = ? masss of solute, NH4NO3 = 35g, molar mass of solute, NH4NO3 = 80g)

molar enthalpy of solution, ΔHsoln = heat absorbed or released ÷ moles of solute, n

ΔHsoln = q ÷ n

q = ΔHsoln × n

moles solute, n = mass solute (g) ÷ molar mass solute (g mol-1)

moles of solute, n = 35g/80g/mol = 0.4375 moles

q = 25700J/mol × 0.4375 mol = 11243.75J

From equation 1 above, ΔT = q / (m × cg) = 11243.75J / (135 × 4.18 J°C-1g-1) = 19.9°C

Since the reaction is endothermic, Tinitial > Tfinal, therefore, Tfinal = Tinitial - ΔT = 27 - 19.9 = 7.1°C

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