Answer:
Explanation:
The structures of the starting materials 2‑methylhept‑3‑yne can be seen in the diagram attached below. We will also notice the role of NaNH₂ which acts as a strong base and whose function is to extract acidic proton and form an alkyne as a product.
The reaction with NaNH₂ yields acetylide ion which is then reacted with a straight-chain alkyl halide to form an extended carbon chain.
CHECK THE DIAGRAM BELOW.
Non-polar Solute and Polar Solvent (and vice versa)
However the molecules in the solute and solvent are only able to make dispersion forces with each other (as they aren't both polar). This only releases very little energy. Therefore overall, more energy is required than released and hence the process won't happen.
Answer: i. The reaction consumes 3 moles of iron(III) oxide.
ii. The reaction produces 3 moles of aluminum oxide and 6 moles of iron.
Explanation:
The balanced reaction is :
![Fe_2O_3(s)+2Al(s)\rightarrow Al_2O_3(s)+2Fe(s)](https://tex.z-dn.net/?f=Fe_2O_3%28s%29%2B2Al%28s%29%5Crightarrow%20Al_2O_3%28s%29%2B2Fe%28s%29)
According to stoichiometry:
a) 2 moles of aluminium consume = 1 mole of ![Fe_2O_3](https://tex.z-dn.net/?f=Fe_2O_3)
6 moles of aluminium consume =
moles of ![Fe_2O_3](https://tex.z-dn.net/?f=Fe_2O_3)
b) 2 moles of aluminium produce = 1 mole of ![Al_2O_3](https://tex.z-dn.net/?f=Al_2O_3)
6 moles of aluminium consume =
moles of ![Al_2O_3](https://tex.z-dn.net/?f=Al_2O_3)
2 moles of aluminium produce = 2 moles of ![Fe](https://tex.z-dn.net/?f=Fe)
6 moles of aluminium consume =
moles of ![Fe](https://tex.z-dn.net/?f=Fe)
Answer:
3.97 x 10²³atoms
Explanation:
Given parameters:
Mass of ammonia = 11.22g
Unknown:
Chemical amount of ammonia present = ?
Solution:
The chemical amount present in a substance is the number of atoms it contains.
To solve this problem, from the given mass find the number of moles first.
Number of moles =
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles =
= 0.66mole
1 mole of any substance contains 6.02 x 10²³ atoms
0.66 mole of ammonia will contain 0.66 x 6.02 x 10²³ atoms
= 3.97 x 10²³atoms