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SCORPION-xisa [38]
3 years ago
13

Below are two parallel lines with a third line intersecting them.

Mathematics
1 answer:
Delicious77 [7]3 years ago
8 0

Answer:

x=50

Step-by-step explanation:

That is becasue they are in the same spot on different parallel lines.

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X+4 divided by x^2+16<br><br> Why can't it be simplified?
KonstantinChe [14]
Let's try to simplify x^2 + 16. It's a sum of two squares:

x^2 + 16 = 0

x^2 = -16

The problem is, we can't take a square root of a negative. This is where imaginary numbers come in.

Remember that square roots have a plus or minus symbol outside:

±√-16 = ±4i

Our two roots are 4i and -4i. Therefore, the trinomial simplifies to:

(x + 4i)(x - 4i)

If we attempt to divide x + 4 by these two binomials, we will find that 4 and 4i are not like terms. Therefore, we can't simplify this expression.
8 0
3 years ago
Simplify the equation. (5xE2 - 3x) - (5xE2 - 3x+1)
s2008m [1.1K]

Answer:

\huge \boxed{\mathrm{-1}}

Step-by-step explanation:

(5xe^2  - 3x) - (5xe^2  - 3x+1)

Distribute negative sign.

5xe^2  - 3x- 5xe^2  +3x-1

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0xe^2 +0x-1

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8 0
3 years ago
What does this equal ?<br> 7000( 1 + 2%/12) ^ (12 • 20)
grigory [225]

Answer:

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Step-by-step explanation:

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3 years ago
What is the value of sec theta given the diagram below?
marishachu [46]

Answer:

\sec \theta=-\sqrt{5}

Step-by-step explanation:

The hypotenuse is h^2=6^2+3^2

h^2=36+9

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h=\sqrt{45}

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The terminal side of \theta is in the second quadrant.

In this quadrant; the secant ratio is negative.

\sec \theta=-\frac{hypotenuse}{adjacent}

\sec \theta=-\frac{3\sqrt{5}}{3}

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6 0
3 years ago
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vredina [299]
The answer is:  [D]:  " y = x² + 2x + 2 " .
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7 0
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