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alexdok [17]
3 years ago
9

3.

Mathematics
1 answer:
kozerog [31]3 years ago
8 0

9514 1404 393

Answer:

  13 units

Step-by-step explanation:

The distance formula is useful for this.

  d = √((x2 -x1)² +(y2 -y1)²)

  d = √((5 -0)² +(8 -(-4))²) = √(25 +144) = √169

  d = 13

The length of AC is 13 units.

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The pool holds 15069 of water and is leaking at a rate of 4 gallons per day how many gallons will remain in the pool after 141 d
Veronika [31]

Answer:

Water remaining in the pool after 141 days = 14,505 gallons

Step-by-step explanation:

Total number of gallons of water in the pool = 15,069

Rate of leakage of water = 4 gallons per day

Using unitary method

1 day leakage of water from the pool = 4 gallons

∴ In 141 days leakage of water from the pool will be = 141\times4=564 gallons

After leaking 564 gallons of water, total gallons of water that will remain in the pool will be = 15,069-564=14,505 gallons

8 0
3 years ago
If x=(-3)to the 3rd power, write an expression that is equal to (-3)to the 6th power
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USE PROCESS OF ELIMINATION
8 0
4 years ago
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Step-by-step explanation:

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4 0
3 years ago
3-5(3a+6)3-5(3a+6) in standard form
WARRIOR [948]

Answer:

-15a-27

Step-by-step explanation:

Given

3-5(3a+6)

Required

Express in standard form

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The standard form of 3-5(3a+6) is -15a-27

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