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3 years ago

Please help me and answer these questions.

Physics

1 answer:

jeka57 [31]3 years ago

3 0

Answer:

Answer 2 is iron.

Answer 3 is magnetic induction.

Explanation:

I hope it's helpful!

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A velocity selector has a magnetic field of magnitude 0.22 T perpendicular to an electric field of magnitude 0.51 MV/m.

ohaa [14]

Answer:

speed of a particle = 2.31 × $10^{6}$ m/s

energy of proton required = 27.77 KeV

energy of electron required = 15.171 eV

Explanation:

given data

magnetic field of magnitude = 0.22 T

electric field of magnitude = 0.51 MV/m

to find out

speed of a particle and energy must protons have to pass through undeflected and energy must electrons have to pass through undeflected

solution

we know that force due to magnetic and electric field is express as

force due to magnetic field B = qvB ..............1

and force due to electric field E = qE .....................2

so without deflection force due to magnetic field = force due to electric field

so here qvB = qE

and V = $\frac{E}{B}$ ...................3

put here value

V = $\frac{0.51*10^6}{0.22}$

speed of a particle = 2.31 × $10^{6}$ m/s

and

now energy of proton required will be here as

energy of proton required = mass of proton × $\frac{V^2}{2}$

put here value

energy of proton required = 1.67 × $10^{-27}$ × $\frac{(2.31*10^6)^2}{2}$

energy of proton required = 4.45 × $10^{-15}$ J

energy of proton required = 4.45 × $10^{-15}$ J ÷ (1.602 × $10^{-19}$

energy of proton required = 27777.777 eV

energy of proton required = 27.77 KeV

and

now we get here energy of electron required that is

energy of electron required = mass of electron × $\frac{V^2}{2}$

put here value

energy of electron required = 9.11 × $10^{-31}$ × $\frac{(2.31*10^6)^2}{2}$

energy of electron required = 24.305× $10^{-19}$ J

energy of electron required = 24.305 × $10^{-19}$ J ÷ (1.602 × $10^{-19}$

energy of electron required = 15.171 eV

5 0

4 years ago

Read 2 more answers

How much force is needed to push a 20kg at 0.2 m/s/s<br> A)10 N<br> B)20 N<br> C)4 N<br> D)40 N

ad-work [718]

Answer:

Explanation:

20x.2=4

4 0

2 years ago

It is well known that runners run more slowly around a curved track than a straight one. One hypothesis to explain this is that

barxatty [35]

Answer:

$percentage = 6.27 %$

Explanation:

As we know that when runner is moving on straight track then the net force on his feet is given as

$F_s = mg$

while when runner is moving on circular track then we have

$F_c = \sqrt{(mg)^2 + (\frac{mv^2}{R})^2}$

$F_c = m\sqrt{g^2 + \frac{v^4}{R^2}}$

$F_c = m\sqrt{9.8^2 + \frac{8^4}{18^2}}$

$F_c = m(10.42)$

now percentage change is given as

$percentage = \frac{F_c - F_s}{F_s} \times 100$

$percentage = \frac{m(10.42) - m(9.81)}{m(9.81)}\times 100$

$percentage = 6.27 %$

6 0

3 years ago

The drawing shows three identical springs hanging from the ceiling. Nothing is attached to the first spring, whereas a 4.5 n blo

Naya [18.7K]

<Continuation of the question>

(a) the spring constant (in N/m) and

(b) the weight of the block hanging from the third spring.

the distance for the first spring is 20cm, the second 35cm, the third 50cm.

Answer:

a) To find the spring constant, we'll use the formula

F=kx, if we make k the subject we'll get

k=F/x, where F=4.5N, x = 35cm - 20cm = 15cm = 0.15m

k=F/x = 4.5N/0.15m = 30N/m is the Answer

b) to find the weight of block hanging on third spring

we use the formula F=kx

where k = 30N/m, x=50cm-20cm=30cm=0.30m

F=kx = (30N/m)*(0.30m) = 9N is the Answer

4 0

3 years ago

1. What is transferred from place to place by waves?

dem82 [27]

Answer:

Energy

Explanation:

A wave is a disturbance that transfers energy from one place to another without transferring matter. Waves transfer energy away from the source, or starting place, of the energy.

6 0

3 years ago