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aalyn [17]
3 years ago
8

A certain amount of a monatomic gas is maintained at constant volume as it is cooled by 50K. This feat is accomplished by removi

ng 400 J of energy from the gas. How much work is done by the gas?
a) 400 J
b) -400 J
c) zero
d) none of the above
Physics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

The correct answer is option a. 400J

Explanation:

Hello!

Let's solve this!

To know if the work is positive or negative we have to know the following:

The work is positive when the gas performs (expansion)

The work is negative when done outside on the gas (compression)

In this case the work is done by the gas, so it is positive.

The correct answer is option a. 400J

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Power can be calculate through the equation,
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It should be noted that velocity is calculated by dividing displacement by time. Thus, from the given in this item we can calculate for the power. 
                       Power = (120 lb) x (12 ft/9 s)
                         <em> </em><span><em>Power   = 160 lb.ft/s</em></span>
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What is the definition of input force?
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Answer:

The input force (effort) is the amount of effort used to push down on a rod, or pull on a rope in order to move the weight. In this example, the force the little guy is using to pull the elephant is the input force.

Explanation:

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2 years ago
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Name a suitable plece of equipment that could be used to measure the length of the pool.​
Fynjy0 [20]

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With a tape measure.

Explanation:

We can use a big tape measure, this tape is in the market and we can use the one with the proper length that lets us measure different sections of the total length of the pool.

4 0
3 years ago
A wire 95.0 mm long is bent in a right angle such that the wire starts at the origin and goes in a straight line to x = 40.0 mm
qaws [65]

Answer:

0.1040512455 N

36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction

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29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction

Explanation:

I = Current

B = Magnetic field

Separation between end points is

l=\sqrt{40^2+55^2}\\\Rightarrow l=68.00735\ mm

Effective force is given by

F=IlB\\\Rightarrow F=5.1\times 68.00735\times 10^{-3}\times 0.3\\\Rightarrow F=0.1040512455\ N

The force is 0.1040512455 N

tan\theta=\dfrac{55}{40}\\\Rightarrow \theta=tan^{-1}\dfrac{55}{40}\\\Rightarrow \theta=53.97^{\circ}

The angle the force makes is given by

\alpha=\theta-90\\\Rightarrow \alpha=53.97-90\\\Rightarrow \alpha=-36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction

The direction is 36.03^{\circ}\ or\ 323.97^{\circ}in\ CCW\ direction

F=IlB\\\Rightarrow F=4.9\times \sqrt{20^2+35^2}\times 10^{-3}\times 0.3\\\Rightarrow F=0.05925\ N

The force is 0.05925 N

tan\theta=\dfrac{35}{20}\\\Rightarrow \theta=tan^{-1}\dfrac{35}{20}\\\Rightarrow \theta=60.26^{\circ}

\alpha=\theta-90\\\Rightarrow \alpha=60.26-90\\\Rightarrow \alpha=-29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction

The direction is 29.74^{\circ}\ or\ 330.26^{\circ}in\ CCW\ direction

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If a spacecraft is pushed by a thruster, what will happen
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D.

This is an accordance with Newton's First Law of Motion, stating that objects in motion remain in motion and objects at rest remain at rest unless acted upon by an external force.
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