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aalyn [17]
3 years ago
8

A certain amount of a monatomic gas is maintained at constant volume as it is cooled by 50K. This feat is accomplished by removi

ng 400 J of energy from the gas. How much work is done by the gas?
a) 400 J
b) -400 J
c) zero
d) none of the above
Physics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

The correct answer is option a. 400J

Explanation:

Hello!

Let's solve this!

To know if the work is positive or negative we have to know the following:

The work is positive when the gas performs (expansion)

The work is negative when done outside on the gas (compression)

In this case the work is done by the gas, so it is positive.

The correct answer is option a. 400J

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A 1,300 kg wrecking ball hits the building at 1.07 m/s2.
dezoksy [38]
So we know F=ma
m means mass and a means acceleration
so Force= ma
so F=1300X1.07=1391N
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7 0
2 years ago
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Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration wo
Nina [5.8K]

Answer:

Acceleration = 0.0282 m/s^2

Distance = 13.98 * 10^12 m

Explanation:

we will apply the energy theorem

work done = ΔK.E ( change in Kinetic energy )  ---- ( 1 )

<em>where :</em>

work done = p * t

                  = 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J

( note : convert 1 year to seconds )

and ΔK.E = 1/2 mVf^2   given ; m = 1200 kg  and initial V = 0

<u>back to equation 1 </u>

473040000 * 10^6  = 1/2 mv^2

Vf^2 = 2(473040000 * 10^6 ) / 1200

∴ Vf = 887918.92 m/s

<u>i) Determine how fast the rocket is ( acceleration of the rocket )</u>

a = Vf / t

  = 887918.92 / ( 1 year )

  = 0.0282 m/s^2

<u>ii) determine distance travelled by rocket </u>

Vf^2 - Vi^2 = 2as

Vi = 0

hence ; Vf^2 = 2as

s ( distance ) =  Vf^2 / ( 2a )

                     = ( 887918.92 )^2 / ( 2 * 0.0282 )

                    = 13.98 * 10^12 m

8 0
3 years ago
NASA is designing a mission to explore Titan, the largest moon of Saturn. Titan has numerous hydrocarbon lakes containing a mix
Vitek1552 [10]

Answer:

Total pressure in atmosphere  IS 4.36 atm

Explanation:

Given Data:

Depth of lake is 400 mtr

surface tension is 147 kilopascals

surface temperature  94 kelvin

Gravity = 1.35 m/s^2

specific gravity of methane(liquid) = 0.415

specific gravity of ethane(liquid) = 0.546

density of methane can be obtained as

\rho_{methane} = 0.415\times 1000 = 415 kg/m^3

Density of ethane can be obtained as

\rho_{ethane} = 0.546\times 1000 = 546 kg/m^3

Total pressure in atmosphere can be obtained as

P = surface\ tension + \rho_{max}gh

 = 147 +546\times 1.35\times 400\times 10^{-3}

  = 441.84 kPa

= 441.84\times 0.009869 atm\kPa

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7 0
2 years ago
Explain the differences in structure and use for life between oxygen gas in the atmosphere and ozone.
navik [9.2K]

Answer:

Most of the oxygen in the atmosphere is in the form of O2, which means it is made up of molecules containing two oxygen atoms. Ozone, however is O3, which means it is made up of molecules containing three oxygen atoms. O2 is what we breath, and what plants release from photosynthesis. Ozone occurs naturally high in the stratosphere, where it absorbs ultraviolet light, protecting us here on the surface from skin cancer. Ozone can also occur closer to the surface of the earth as a pollutant. It is formed from reactions with O2 and chemicals emitted from factories and cars. It comes in the form of smog.

So in general:

Oxygen (O2): Essential to human life

Ozone (O3) in the stratosphere: essential to protecting life on earth

Ozone (O3) on the surface of the earth: toxic to human life, caused by pollution

5 0
2 years ago
Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air
frosja888 [35]

The frequency of the wave has not changed.

In fact, the frequency of a wave is given by:

f=\frac{v}{\lambda}

where v is the wave's speed and \lambda is the wavelength.

Applying the formula:

- In air, the frequency of the wave is:

f=\frac{400 m/s}{2 m}=200 Hz

- underwater, the frequency of the wave is:

f=\frac{1600 m/s}{8 m}=200 Hz

So, the frequency has not changed.

3 0
3 years ago
Read 2 more answers
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