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kogti [31]
2 years ago
11

An astronaut whose mass is 80 kg carries an empty oxygen tank with a mass of 10 kg. The astronaut throws the tank away with a sp

eed of 2.0 m/s. With what velocity does the astronaut start to move off into space?
Physics
1 answer:
yan [13]2 years ago
6 0

Answer:

The speed of the astronaut is 0.25 m/s in the opposite direction to the oxygen tank.

Explanation:

Using the conservation of linear momentum, we have:

p_{initial}=p_{final}

The initial momentum is zero because both of them are at rest, so we just have a final momentum.

0=m_{astro}V_{f-astro}+m_{tank}V_{f-tank}

m_{astro}V_{f-astro}=-m_{tank}V_{f-tank}

V_{f-astro}=-\frac{V_{f-tank}m_{tank}}{m_{astro}}

V_{f-astro}=-\frac{2*10}{80}

V_{f-astro}=-0.25\: m/s

Therefore, the speed of the astronaut is 0.25 m/s in the opposite direction to the oxygen tank.

I hope it helps you!  

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2 years ago
Calculate the magnitude of the gravitational force exerted by the Moon on a 79 kg human standing on the surface of the Moon. (Th
Luden [163]

Answer:

F= 134.92 N

Explanation:

Given that

The mass of the moon ,M = 7.4 x 10²² kg

The mass of the man ,m = 79 kg

The radius ,R= 1.7 x 10⁶ m

The force exerted by moon is given as

F=G\dfrac{Mm}{R^2}

Now by putting the values in the above equation we get

F=6.67\times 10^{-11}\times \dfrac{79\times 7.4\times 10^{22}}{(1.7\times 10^6)^2}\ N\\F=134.92 N

Therefore the force will be 134.92 N.

F= 134.92 N

8 0
3 years ago
Sir Dudley the Dextrous is loading cannons on top of the castle's tallest towers in preparation for an expected attack. He slips
JulsSmile [24]

Answer:

6667.9 J

Explanation:

We are given that

Mass of cannon.m=14 kg

Time,t=3.15 s

Initial velocity,u=0

We have to find the work done by gravity on the falling cannon ball.

g=9.8 m/s^2

h=ut+\frac{1}{2}gt^2

Substitute the values

h=0+\frac{1}{2}\times 9.8\times (3.15)^2=48.6 m

Work done,W=mgh

Using the formula

W=14\times 9.8\times 48.6=6667.9 J

4 0
3 years ago
What is the magnetic force value due to 3.5nanocoloumb charge moves to the
sertanlavr [38]

The force on the charge is 1.1×10⁻⁸ N.

<h3>What is force?</h3>

Force can be defined as the product of the mass of a body and its acceleration

To calculate the force on the charge, we use the formula below.

Formula:

  • F = qvBsin∅............. Equation 1

Where:

  • q = charge
  • v = velocity
  • B = magnetic field
  • ∅ = Angle.

From the question,

Given:

  • B = 25 mT = 0.025 T
  • v = 250 m/s
  • q = 3.5 nC = 3.5×10⁻⁹ C
  • ∅ = 30°

Substitute the given values into equation 1

  • F = (0.025)(250)(3.5×10⁻⁹)(sin30°)
  • F = 1.093×10⁻⁸ N
  • F ≈ 1.1×10⁻⁸ N

Hence, the force on the charge is 1.1×10⁻⁸ N.

Learn more about force here: brainly.com/question/12970081




6 0
2 years ago
The red light emitted by a helium–neon laser has a wavelength of 632.8 nm. What is the frequency of the light waves?
Monica [59]

f = 4.74 × 10 ^14  Hz

hope this helps:)

5 0
3 years ago
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