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kogti [31]
2 years ago
11

An astronaut whose mass is 80 kg carries an empty oxygen tank with a mass of 10 kg. The astronaut throws the tank away with a sp

eed of 2.0 m/s. With what velocity does the astronaut start to move off into space?
Physics
1 answer:
yan [13]2 years ago
6 0

Answer:

The speed of the astronaut is 0.25 m/s in the opposite direction to the oxygen tank.

Explanation:

Using the conservation of linear momentum, we have:

p_{initial}=p_{final}

The initial momentum is zero because both of them are at rest, so we just have a final momentum.

0=m_{astro}V_{f-astro}+m_{tank}V_{f-tank}

m_{astro}V_{f-astro}=-m_{tank}V_{f-tank}

V_{f-astro}=-\frac{V_{f-tank}m_{tank}}{m_{astro}}

V_{f-astro}=-\frac{2*10}{80}

V_{f-astro}=-0.25\: m/s

Therefore, the speed of the astronaut is 0.25 m/s in the opposite direction to the oxygen tank.

I hope it helps you!  

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Explanation:

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         \frac{p}{dt} = \frac{W}{c}

                  F = \frac{2IA}{c}

                     = \frac{2 (1000 W/m^{2})(5.5 \times 10^{3} m)^{2}}{3 \times 10^{8} m/s}

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Why is it sometimes difficult for scientists to identify a a fold or fault?
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Folds and faults are difficult to identify because they occur in the interior of rocks and also due to the dense nature of the materials.

<h3>What are faults and folds?</h3>

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Folds occurs when infolds occur in materials.

Faults and folds usually occur in rocks.

Folds and faults are difficult to identify because they occur internally and also due to the dense nature of the materials.

Learn more about faults and folds at: brainly.com/question/14240712

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2 years ago
A spherical drop of water carrying a charge of 42 pC has a potential of 620 V at its surface (with V = 0 at infinity). (a) What
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Answer:

0.0006091222 m

Explanation:

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Electric potential is given by (at r = R)

V=\dfrac{q}{4\pi\epsilon R}\\\Rightarrow R=\dfrac{q}{4\pi\epsilon V}\\\Rightarrow R=\dfrac{42\times 10^{-12}}{4\pi\times 8.85\times 10^{-12}\times 620}\\\Rightarrow R=0.0006091222\ m

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faltersainse [42]

Answer:

Cp = 4756 [J/kg*°C]

Explanation:

In order to calculate the specific heat of water, we must use the equation of energy for heat or heat transfer equation.

Q = m*Cp*(T_f - T_i)/t

where:

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m = mass of the water = 0.8 [kg]

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T_i = initial temperature of the water = 18 [°C]

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Now clearing the Cp, we have:

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Now replacing

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