Answer:
(a) Vf = 128 ft/s
(b) K.E = 122.8 Btu
Explanation:
(a)
In order to find the velocity of the object just before striking the surface of earth or the final velocity, we use 3rd equation of motion:
2gh = Vf² - Vi²
where,
g = 32.2 ft/s²
h = height = 253 ft
Vf = Final Velocity = ?
Vi = Initial Velocity = 10 ft/s
Therefore,
(2)(32.2 ft/s²)(253 ft) = Vf² - (10 ft/s)²
16293.2 ft²/s² + 100 ft²/s² = Vf²
Vf = √(16393.2 ft²/s²)
<u>Vf = 128 ft/s</u>
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(b)
The kinetic energy of the object before it hits the surface of earth is given by:
K.E = (0.5)(m)(Vf)²
where,
m = mass of object = 375 lb
K.E = Kinetic energy of object before it strikes the surface of earth = ?
Therefore,
K.E = (0.5)(375 lb)(128 ft/s)²
K.E = 3073725 lb.ft²/s²
Now, converting this to Btu:
K.E = (3073725 lb.ft²/s²)(1 Btu/25037 lb.ft²/s²)
<u>K.E = 122.8 Btu</u>
Answer:
There is no place for first person in formal academic argumentative essay. However, you can use first person only if it has been asked to provide your personal opinion or reflection about the topic.
Explanation:
Answer:
As the mass of an object increases, its gravitational force increases.
As an object's distance to other objects increases, its gravitational force on those objects increases.
Explanation:
The gravitational force of one object on another is calculated with the equation
F = (G*m1*m2)/(r²),
where G is the gravitational constant,
M1 and M2 are the masses of the two objects, and
r is the distance between them
We can see that the force has a direct relationship with both of the mass values, and an inverse square relationship with the distance between them.
Hope this helped!
Answer:
The magnitude of the electric field strength = 7.2 x 10⁸ N/C
Explanation:
The linear density:
Point r = 3 cm = 3/100 m
r = 0.03 m
The electric field strength is calculated below
The magnitude of the electric field strength = 7.2 x 10⁸ N/C
